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4 years ago

7

What is radius of 4 km?

1 answer:

AysviL [449]4 years ago

7 0

Answer:

A) 50.3 km

Not sure........

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In Jayce's favorite video game, he collects stars to earn points. Today, he collected 80 silver stars and earned 160 points. He

tiny-mole [99]

Silver stars are worth 2 and gold stars are each worth 5

4 0

3 years ago

Read 2 more answers

The perimeter of a rectangle is 68 ft.

inessss [21]

Let the length be 9x and the width = 8x
Perimeter = 2(l + w) = 2(9x + 8x) = 2(17x) = 34x = 68
x = 68/34 = 2
9x = 9(2) = 18 ft
8x = 8(2) = 16 ft
Therefore, dimensions are 18 ft by 16ft

5 0

3 years ago

Clara has a purse in the shape of a trapezoid the top of the purse measures 22 cm while the bottom of the part measures 36 cm if

pashok25 [27]

The height of purse which is in trapezoid shape is 26 cm

<em><u>Solution:</u></em>

Clara has a purse in the shape of a trapezoid

<em><u>The area of trapezoid is given by formula:</u></em>

$Area = \frac{a+b}{2} \times h$

Where,

"h" is the height

"a" and "b" are the parallel sides length

From given,

Area = 754 cm

a = 22 cm

b = 36 cm

h = ?

<em><u>Substituting the values in formula,</u></em>

$754 = \frac{22+36}{2} \times h\\\\754 = \frac{58}{2} \times h\\\\Simplify\ the\ above\ expression\\\\754 = 29h\\\\Divide\ both\ sides\ of\ equation\ by\ 29\\\\h = 26$

Thus height of purse which is in trapezoid shape is 26 cm

8 0

4 years ago

If f(x)= x squared and g(x)=2x^3- x squared, find f(x)-g(x).

tankabanditka [31]

Answer:

$f(x)-g(x)=2x^2(1-x)$

Step-by-step explanation:

Given that,

$f(x)=x^2\\\\g(x)=2x^3-x^2$

We need to find the value of f(x)-g(x).

Put the values of f(x) and g(x). So,

$f(x)-g(x)=x^2-(2x^3-x^2)\\\\=x^2-2x^3+x^2\\\\=2x^2-2x^3\\\\=2x^2(1-x)$

So, the value of f(x)-g(x) is equal to $2x^2(1-x)$ .

3 0

3 years ago

Negative two plus seven-x over nine equals negative one.

Akimi4 [234]

Answer: 9/7 or 1.3 (rounded)

reasoning: -2 + 7x/9 = -1
7x/9 = 1
7x = 9
x = 9/7, or 1.3 (assuming they allow you to round to the nearest tenth)

6 0

3 years ago