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taurus [48]
3 years ago
8

A small company plans to invest in a new advertising campaign. There is a 25% chance that the company will loose $10,000, a 55%

chance of a break even, and a 20% chance of a $15,000 profit. Based only on this information, what should the company do?
Mathematics
1 answer:
charle [14.2K]3 years ago
8 0

Answer:

but look at yotube the awncer is on there

Step-by-step explanation:

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3 years ago
Solve the following please:
Reika [66]

Answer:21

Step-by-step explanation: solve whats in the numerator then solve whats in the denominator then you divide

6 0
2 years ago
Yvonne wants to cover the back of her smartphone with a decorative pattern. If the phone's length is 1/2 foot and width is 1/6 f
allochka39001 [22]

Answer:

1/12 square foot

Step-by-step explanation:

Area of the pattern = LEngth * Width

Given the following

Length = 1/2 foot

Width = 1/6 foot

Area of the pattern = 1/2 * 1/6

Area of the pattern  =1/12 square foot

Hence the area that the decorative pattern will cover will be 1/12 square foot

4 0
3 years ago
Estimate the difference: 3 2/5 - 5/8
svet-max [94.6K]

Answer: 3

Step-by-step explanation: Half of 5 is 2.5 so 3 2/5 will be estimated to a 3 1/2 and 5/8 is very close to 4 which is half of 8. so 5/8 will be estimated to 1/2! Both of them subtracted is gonna be 3 because 1/2 - 1/2 is 0!

Have a great day!

5 0
2 years ago
Maths functions question!!
Marina86 [1]

Answer:

5)  DE = 7 units and DF = 4 units

6)  ST = 8 units

\textsf{7)} \quad \sf OM=\dfrac{3}{2}\:units

8)  x ≤ -3 and x ≥ 3

Step-by-step explanation:

<u>Information from Parts 1-4:</u>

brainly.com/question/28193969

  • f(x)=-x+3
  • g(x)=x^2-9
  • A = (3, 0)  and C = (-3, 0)

<h3><u>Part (5)</u></h3>

Points A and D are the <u>points of intersection</u> of the two functions.  

To find the x-values of the points of intersection, equate the two functions and solve for x:

\implies g(x)=f(x)

\implies x^2-9=-x+3

\implies x^2+x-12=0

\implies x^2+4x-3x-12=0

\implies x(x+4)-3(x+4)=0

\implies (x-3)(x+4)=0

Apply the zero-product property:

\implies (x-3)= \implies x=3

\implies (x+4)=0 \implies x=-4

From inspection of the graph, we can see that the x-value of point D is <u>negative</u>, therefore the x-value of point D is x = -4.

To find the y-value of point D, substitute the found value of x into one of the functions:

\implies f(-4)=-(-4)=7

Therefore, D = (-4, 7).

The length of DE is the difference between the y-value of D and the x-axis:

⇒ DE = 7 units

The length of DF is the difference between the x-value of D and the x-axis:

⇒ DF = 4 units

<h3><u>Part (6)</u></h3>

To find point S, substitute the x-value of point T into function g(x):

\implies g(4)=(4)^2-9=7

Therefore, S = (4, 7).

The length ST is the difference between the y-values of points S and T:

\implies ST=y_S-y_T=7-(-1)=8

Therefore, ST = 8 units.

<h3><u>Part (7)</u></h3>

The given length of QR (⁴⁵/₄) is the difference between the functions at the same value of x.  To find the x-value of points Q and R (and therefore the x-value of point M), subtract g(x) from f(x) and equate to QR, then solve for x:

\implies f(x)-g(x)=QR

\implies -x+3-(x^2-9)=\dfrac{45}{4}

\implies -x+3-x^2+9=\dfrac{45}{4}

\implies -x^2-x+\dfrac{3}{4}=0

\implies -4\left(-x^2-x+\dfrac{3}{4}\right)=-4(0)

\implies 4x^2+4x-3=0

\implies 4x^2+6x-2x-3=0

\implies 2x(2x+3)-1(2x+3)=0

\implies (2x-1)(2x+3)=0

Apply the zero-product property:

\implies (2x-1)=0 \implies x=\dfrac{1}{2}

\implies (2x+3)=0 \implies x=-\dfrac{3}{2}

As the x-value of points M, Q and P is negative, x = -³/₂.

Length OM is the difference between the x-values of points M and the origin O:

\implies x_O-x_m=o-(-\frac{3}{2})=\dfrac{3}{2}

Therefore, OM = ³/₂ units.

<h3><u>Part (8)</u></h3>

The values of x for which g(x) ≥ 0 are the values of x when the parabola is above the x-axis.

Therefore, g(x) ≥ 0 when x ≤ -3 and x ≥ 3.

8 0
1 year ago
Read 2 more answers
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