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Molodets [167]
3 years ago
14

Please help me!!!!! What are the vales of x and y?

Mathematics
1 answer:
liberstina [14]3 years ago
4 0

Answer:

i only no y, y=4 I hope this helps

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A) 11 and 12<br> B) 8 and 9<br> C 10 and 11<br> D 76 and 78
Valentin [98]

Answer:

B

Step-by-step explanation:

7 0
3 years ago
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Need help using synthetic division! ​
viktelen [127]

Answer:

3x^{2} -3x+8-\frac{9}{x+1}

Step-by-step explanation:

Since we're dividing the polynomial by (x+1), we'll be using -1 to start the division.

Before setting the division up, let's list the coefficients of x from descending powers and the constant.

The coefficient of x^{3} is 3

Since we don't see an x^{2}, the coefficient will be 0.

The coefficient of x is 5.

Lastly, the constant, which is the term without the x is -1.

Refer to the attached picture before continuing.

After referring to the picture, we now have the coefficients for the quotient.

The coefficient of x^{2} is 3.

The coefficient of x is -3.

The constant is 8.

Lastly, since the last number is not zero, it's the remainder just like regular division. This can be tricky to remember, but -9 is not the actual remainder.

The remainder is actually \frac{-9}{x+1}.

Now putting all the pieces together, we get:

3x^{2} -3x+8-\frac{9}{x+1}

3 0
2 years ago
(a) The probability that an automobile being filled with gasoline will also need an oil change is 0.35; the probability that it
cricket20 [7]

Answer:

0.714 ; 0.556 ; (A1 n A2 n A3) = 0

Step-by-step explanation:

Given that :

P(oil) = 0.35

P(filter) = 0.45

P(oil n filter) = 0.25

1)

P(filter | Oil) = P(oil n filter) / P(oil)

P(filter | Oil) = 0.25 / 0.35 = 0.714

11)

P(Oil | filter) = P(oil n filter) / P(filter)

P(Oil | filter ) = 0.25 / 0.45 = 0.556

Number of red aces = 2

Queen or king = 4 + 4 = 8

Number on card greater than 3 and less than 8 = {4,5,6,7} = 4 card ; for 4 suits = 4 * 4 = 16

Total number of cards in deck = 52

Choosing without replacement :

Hence,

A1 = 2 / 52

A2 = 8 / 51

A3 = 16 / 50

(A1 n A2 n A3) ;this means card common to all three events.

However, (A1 n A2 n A3) = 0 because ;

1.) No red ace card is greater than 3 and less than 8.

11.) An ace card can neither be a king nor a queen

3 0
3 years ago
What expression is equivalent to (5z2+32+2)?
erica [24]

Answer:

10z+34

Step-by-step explanation:

3 0
3 years ago
Assume the competing hypotheses take the following form: H0: µ1 – µ2 = 0, HA: µ1 – µ2 ≠ 0, where µ1 is the population mean for p
DedPeter [7]

Answer:

t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }

Step-by-step explanation:

H0: µ1 – µ2 = 0

HA: µ1 – µ2 ≠ 0

We have given,

The population variances are not known and cannot be assumed equal.

The test statistic for the test is

t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }

Where,

\bar x_1 = sample meaan of population 1

\bar x_2 = sample mean of population 2

n_1 = sample size of population 1

n_2 = sample size of population 2

Therefore, this is the test

t=\frac{\bar x_1- \bar x_2}{\sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2} } }

7 0
3 years ago
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