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Oksana_A [137]
3 years ago
6

Thanks for the help guys

Mathematics
2 answers:
kobusy [5.1K]3 years ago
7 0

i dont really see your question but ok....

Monica [59]3 years ago
3 0

Answer:

Um.... Your welcome(confuse face), but also I see you got a bad grade. I wish I could've help you at least you would've gotten one answer right.

Step-by-step explanation:

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Evaluate 1 3 m − 1 − 1 2 n 3 1 ​ m−1− 2 1 ​ nstart fraction, 1, divided by, 3, end fraction, m, minus, 1, minus, start fraction,
luda_lava [24]

Answer:

  0

Step-by-step explanation:

Apparently, you want the value of ...

  \dfrac{1}{3}m-1-\dfrac{1}{2}n = \dfrac{m}{3}-\dfrac{n}{2}-1\\\\=\dfrac{21}{3}-\dfrac{12}{2}-1=7-6-1\\\\=\boxed{0}

The value of the given expression for the given variable values is zero.

3 0
3 years ago
in a basket of carrots 12% of them are rotten if 42 carrots are rotten how many carrots are in the basket​
meriva

Answer:

356 hope this is correct :)

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
A rectangle has a height of t^2+7t+6t
jek_recluse [69]

Answer:

2t^3+15t^2+19t+6

Step-by-step explanation:

Height of the Rectangle=t^2+7t+6

Width of the Rectangle=2t+1

Area of the Rectangle = Height X Width

=(2t+1)(t^2+7t+6)\\=2t(t^2+7t+6)+1(t^2+7t+6)\\=2t^3+14t^2+12t+t^2+7t+6\\$Collect like terms\\=2t^3+14t^2+t^2+12t+7t+6\\Area=2t^3+15t^2+19t+6\\

The area of the rectangle is 2t^3+15t^2+19t+6

4 0
3 years ago
Can someone help. Write a word problem about equal groups and act it out to solve
Alona [7]

Answer:

HOPE THAT MAY HELP YOU :)

Step-by-step explanation:

Equal groups are illustrations of using the same variable.

A word problem that uses equal group is:  

Christopher traveled a distance of 5 miles yesterday; he traveled a distance of 4 miles earlier today. Calculate the total distance traveled  

The only condition for equal groups is that:  

The units or variable must be the same  

For instance:

Add 5 miles and 4 miles ----- This represents distance

Remove 2 liters from 7 liters --- This represents volume

Add 5 hours and quarter of an hour -- This represents time

And so on.

5 0
3 years ago
The Cunninghams are moving across the country. Mr. Cunningham leaves 3 hours before Mrs. Cunningham. If he averages 40mph and sh
svp [43]
Recall your d = rt, distance = rate * time

now, if say, by the time they meet, Mr Cunningham has travelled "d" miles, that means Mrs Cunningham must also had travelled "d" miles as well.

However, he left 3 hours earlier, so by the time he travelled "d" miles, and took say "t" hours, for her it took 3 hour less, because she started driving 3 hours later, so, she's been on the road 3 hours less than Mr Cunningham, so by the time they meet, Mrs Cunningham has travelled then "t - 3" hours.

\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{Mr Cunningham}&d&40&t\\
\textit{Mrs Cunningham}&d&80&t-3
\end{array}
\\\\\\
\begin{cases}
\boxed{d}=40t\\
d=80(t-3)\\
----------\\
\boxed{40t}=80(t-3)
\end{cases}
\\\\\\
\cfrac{40t}{80}=t-3\implies \cfrac{t}{2}=t-3\implies t=2t-6\implies 6=2t-t
\\\\\\
6=t
5 0
3 years ago
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