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deff fn [24]
4 years ago
7

Guys please help with 5 and 6 please. A lot of points

Mathematics
1 answer:
Nimfa-mama [501]4 years ago
6 0
5) Perimeter equals all the sides, and a rectangle has two pairs of equal length sides. If one side is 10 and the other is n, the perimeter would be 2n+20.
Area equals length times width, in this case 10 times n, which just equals 10n.

We can use the same logic for 6.
(7)+(7)+(y+2)+(y+2) = 2y+18 for the perimeter

You just have to use the distributive property to find the area, but it’s still length times width.

7(y+2) = 7y + 14.


Tl;dr
5: 2n+20 and 10n
6: 2y+18 and 7y+14

Hope this helps!
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Answer:

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In ΔABC and ΔDBE

DE || AC   [Given]

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Line segment  AB is transversal that intersects two parallel lines.  [Conclusion from statement 1.]

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\angle BEC \cong \angle BCA

Reflexive property of equality states that if angles in geometric figures can be congruent to themselves.

by Reflexive property of equality:

\angle B \cong \angle B  

By AAA (Angle Angle Angle) similarity postulates states that all three pairs of corresponding angles are the same then, the triangles are similar

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\triangle ABC \sim \triangle DBE

Similar triangles are triangles with equal corresponding angles and proportionate side.

then, we have;

\frac{BD}{BA}                  [By definition of similar triangles]

therefore, the missing statement and the reasons are

Statement                                                                   Reason

3.\angle BDE \cong \angle BAC      Corresponding angles theorem

and  \angle BEC \cong \angle BCA        

5. \triangle ABC \sim \triangle DBE   AAA similarity postulates    

6. BD over BA                                                    Definition of similar triangle



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