Choose two transformations that could have been performed on triangle JKL to form congruent triangle J"K"L".

Mathematics

1 answer:

Svetllana [295]3 years ago

3 0

Triangle JKL was rotated 90° counterclockwise and then refrected across the line y = -4.

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my hw write find an equation of the line passing through (-2,3) and (4,-5) I have to write the equation in slope-intercept form

Viefleur [7K]

Answer:

The line passing through the given points is:

$y=-\frac{4}{3}x+\frac{1}{3}$

in its slope-intercept form

Step-by-step explanation:

Start by finding the slope of the segment that joins the two given points using the slope formula:

$slope=\frac{y_2-y_1}{x_2-x_1}$

which for our case renders:

$slope=\frac{3-(-5)}{-2-4}=\frac{8}{-6} =-\frac{4}{3}$

Now we can find the y-intercept by using any one of the given points in the general slope-intercept form of a line with this slope:

$y=-\frac{4}{3} x+b\\3=-\frac{4}{3} (-2)+b\\3=\frac{8}{3}+b\\b=3-\frac{8}{3} \\b=\frac{9-8}{3} \\b=\frac{1}{3}$

Therefore, the equation of the line becomes:

$y=-\frac{4}{3}x+\frac{1}{3}$

3 0

3 years ago

Please just answer this and explain how to solve...i’m not grasping the work :/

OverLord2011 [107]

$\bf Step-by-step~explanation:$

We are given that BA is perpendicular to BD, so that must mean that m∠ABD is a right angle, or 90º. This means: (8x - 10) + (4x + 52) = 90º, since both of the angles add up to become a right angle. We have to solve for x in order to find m∠CBD.

PART 1

$\bf Step~1:$

Equation: (8x - 10) + (4x + 52) = 90

Let's add the like values together first.

$\bf 8x+4x=12x\\-10+52 = 42$

$\bf 12x+42=90$

$\bf Step~2:$

Let's subtract 42 from both sides of the equation to isolate the variable we are solving for, x. Our goal is to isolate it completely to get a value that is equal to x.

$\bf12x+42(-42)=90(=42)\\12x=48$