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Amiraneli [1.4K]
2 years ago
6

HELLLLLP I AM RUNNIG OUT OF TIMEEEEEE I WILL MARK YOU BRILLLLLLLL

Mathematics
2 answers:
likoan [24]2 years ago
7 0

Answer:

A. 8

Step-by-step explanation:

16+y=24

16+8=24

Therfore the answer is A

Artemon [7]2 years ago
7 0
16 + y = 24
subtract 16 from both sides
y = 8

ANSWER: A
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padilas [110]
-root 3*63x^2 is the answer you want
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how many 4 digit numbers n have the property that the 3 digit number obtained by removing the leftmost digit is one ninth of n
Tom [10]

Answer:

  7

Step-by-step explanation:

We want to find the number 4-digit of positive integers n such that removing the thousands digit divides the number by 9.

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Let the thousands digit be 'd'. Then we want to find the integer solutions to ...

  n -1000d = n/9

  n -n/9 = 1000d . . . . . . add 1000d -n/9

  8n = 9000d . . . . . . . . multiply by 9

  n = 1125d . . . . . . . . . divide by 8

The values of d that will give a suitable 4-digit value of n are 1 through 7.

When d=8, n is 9000. Removing the 9 gives 0, not 1000.

When d=9, n is 10125, not a 4-digit number.

There are 7 4-digit numbers such that removing the thousands digit gives 1/9 of the number.

8 0
2 years ago
What are the steps for using a compass and straightedge to construct a square?   Drag and drop the steps in order from start to
denis-greek [22]
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Find the area of the trapezoid by decomposing it into other shapes. A) 157 cm2 B) 163 cm2 C) 167 cm2 D) 171 cm2
tangare [24]

Answer:

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Step-by-step explanation:

7 0
3 years ago
2. Sue is buying a 13-pound mixture of gummy candy, jelly beans, and hard candy. The cost of gummy candy is $1.20 per pound, jel
omeli [17]

Answer:

Store used 7.5 pounds of gummy candy, 2.5 pounds of jelly beans, and 3 pounds of hard candy.

Step-by-step explanation:

Let the amount of gummy candy be 'x'.

Let the amount of jelly beans be 'y'.

Let the amount of hard candy 'z'.

Now Given:

Sue is buying 13 pound of mixture.

So we can say that;

x+y+z =13

But Given:

The mixture calls for three times as many gummy candy pieces as jelly beans.

x=3y

Substituting the value of x in above equation we get;

3y+y+z=13\\\\4y +z =13 \ \ \ \ \ equation \ 1

Also Given:

cost of gummy candy = $1.20

cost of jelly beans = $2.00

cost of hard candy = $2.60

Total Cost of mixture  = $21.80

Now Total Cost of mixture is equal to cost of gummy candy multiplied amount of gummy candy plus cost of jelly bean multiplied amount of jelly bean plus cost of hard candy multiplied amount of hard candy.

framing in equation form we get;

1.2x+2y+2.6z=21.80

But  x=3y

So 1.2(3y)+2y+2.6z=21.80\\\\3.6y+2y+2.6z=21.80\\\\5.6y+2.6z=21.80

Now Multiplying by both side by 10 we get;

10(5.6y+2.6z)=21.80\times 10\\\\10\times5.6y + 10\times2.6z =218\\\\56y+26z=218 \ \ \ \ \ equation \ 2

Now Multiplying equation 1 by 14 we get;

14(4y +z) =13\times14\\\\14\times4y +14z =182\\\\56y+14z=182

Now Subtracting equation 3 from equation 2 we get;

(56y+26z) - (56y+14z) =218-182\\\\56y +26z-56y-14z=36\\\\12z=36\\\\z=\frac{36}{12} = 3 \ pounds

Now Substituting value of z in equation 1 we get;

4y+z=13\\\\4y+3=13\\\\4y=13-3\\\\4y = 10\\\\y=\frac{10}{4} = 2.5 \ pounds

Now also;

x= 3y\\\\x =3\times2.5 =7.5 \ pounds

Hence Store used 7.5 pounds of gummy candy, 2.5 pounds of jelly beans, and 3 pounds of hard candy.

6 0
3 years ago
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