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Viktor [21]
3 years ago
10

The function f(x) is shown below.

Mathematics
1 answer:
-Dominant- [34]3 years ago
4 0

f(g(x))=x when g(x)=f^{-1}(x)

So f(g(2))=2

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Which function represents the given graph?
andrezito [222]

Answer:

The first equation, f(x)=100(3/5)^(x), represent the graph

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3 years ago
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Please help me.<br><br>List the sides of MNP in ascending order:<br>m&lt; M = 15, m &lt; N= 75
oksian1 [2.3K]

Answer:

Take a look at this: brainly.com/question/14269575?referrer=searchResults

Step-by-step explanation:

6 0
2 years ago
The accountant charged $35 for the first hour of work and $23 for each hour after that.He earned a total of$127 how many hours d
dexar [7]

Answer:

He worked a total of 5 hours.

Step-by-step explanation:

The first hour the man makes $35 dollars for the first hour then for the other hours he earns $23 dollars, right? So we start off with 35.

35 = one hour.

35 + 23 = 2 hours .  =  58.

35  + 23 + 23 = 3 hours. =  81.

35 + 23 + 23 + 23 = 4 hours.  =  104.

35 + 23 + 23 + 23 + 23 = 5 hours. =  127.

We were looking for if the man earned $127 dollars how many hours would be be working.


He'd be working 5 hours.

Hope this helps (:


5 0
3 years ago
if tom has 6 apple and he gave his mom 3 apple and and she made a apple pie how many apple are left. ​
ch4aika [34]

Answer:

depends, if he has 6 then he still has 6

if he gave her 3 of his six, then ate the pies, he has 3

Step-by-step explanation:

5 0
3 years ago
Soap films and bubbles are colorful because the interference conditions depend on the angle of illumination (which we aren't cov
mylen [45]

Answer:

56.39 nm

Step-by-step explanation:

In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,

2t=(m+\frac{1}{2} ).\frac{\lambda}{n}

where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...

Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.

In order to have its longest constructive reflection at the red end (700 nm)

t_1=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_1=\frac{1}{2} .\frac{700}{(2)*(1.33)}\\ \\ t_1=131.58\ nm

Here we take m=0.

Similarly for the constructive reflection at the blue end (400 nm)

t_2=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_2=\frac{1}{2} .\frac{400}{(2)*(1.33)}\\ \\ t_2=75.19\ nm

Hence the thickness difference should be

t_1-t_2=131.58-75.19=56.39 \ nm

7 0
3 years ago
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