Answer:
Looking at the graphic, if a 45-45-90 triangle has a hypotenuse of 1, then each of the side lengths equal 1 / square root (2)
Source: https://www.1728.org/trig2.htm
Step-by-step explanation:
For a), this is clearly a given as it is literally to the right of where it says “Given:”
For b), since ON bisects ∠JOH, this means that it splits it into two separate angles - JON and HON, which are similar due to that bisects mean that it splits it equally into two halves
For c), since NO is the same thing as NO, it is equal to itself
For d), since AAS (angle-angle-side) congruence states that if there are two angles that are congruent (proved in a) and b) ) as well as that a side is congruent (proved in c) ), two triangles are congruent
For e), since two triangles are congruent, every side must have one side that it matches up to in the other triangle. As the opposite side of angle H is JO and the opposite side of angle J is OH, and ∠J=∠H, those two are congruent. As JN and HN are the two sides left, they must be congruent.
Feel free to ask further questions!
6/12=X/18
Using the ratio of 18:12, you multiply 18/12 with 6, which equals 9.
Answer: NJ=9
The answer is 54 degrees I took the exam I got it right
Answer:
Step-by-step explanation:
If we assume that the angle at A is 90 degrees.. which it does seem like it would be. then use that the sum of the angles around the inside of a right triagle is 180 . so you have
180 = 37 + 90 + x
53° = x
does that help?
