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4 years ago

5

Find the solution set of each inequality below and then determine which inequalities have the same solution set as 1/3(-5x-3) &l

t;14

1 answer:

mario62 [17]4 years ago

5 0

1/3(-5x - 3) < 14

-5/3 x - 1 < 14

-5/3 x < 15

-5 x < 45

-x < 9

x > 9

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50 POINTSSSS!!!!!!! HELP ASAP<br><br> DONT SCAM PLS

Anit [1.1K]

The factorization of the expression 36x⁴y³ - 16x³y is 4x³y(9xy² - 4)

<h3>Factorization</h3>

Factorization or factoring is defined as the breaking or decomposition of an entity (for example a number, a matrix, or a polynomial) into a product of another entity, or factors, which when multiplied together give the original number. Factorization of an algebraic expression means writing the given expression as a product of its factors. These factors can be numbers, variables, or an algebraic expression.

To the factor, a number means to break it up into numbers that can be multiplied to get the original number.

In the given expression, 36x⁴y³ - 16x³y can be factorized as

36x⁴y³ - 16x³y = 4x³y(9xy² - 4)

The common factor in the expression is 4x³y

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1 year ago

Which is greater 5.75 or 5.750

Vitek1552 [10]

They are equal to each other.

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4 years ago

Read 2 more answers

\root(3)(-3)\root(3)(-5)=\root(3)(15) true or false

Oksi-84 [34.3K]

The equation $\sqrt[3]{-3} \cdot \sqrt[3]{-5} = \sqrt[3]{15}$ is true

<h3>How to determine the true statement?</h3>

The equation is given as

$\sqrt[3]{-3} \cdot \sqrt[3]{-5} = \sqrt[3]{15}$

Apply the law of indices

$\sqrt[3]{-3 * -5} = \sqrt[3]{15}$

Evaluate the product

$\sqrt[3]{15} = \sqrt[3]{15}$

Both sides of the equation are the same

Hence, the equation $\sqrt[3]{-3} \cdot \sqrt[3]{-5} = \sqrt[3]{15}$ is true

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2 years ago

If y is proportional to x, and y = 4 when x = 6, what is the constant of proportionality between them (the ratio of x to y)

Amanda [17]

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6 0

3 years ago

Eli attended a concert. The decibel level of the music averaged 110 decibels but varied by 28 decibels from the average. Enter a

musickatia [10]

Answer:

The decibel range is $82\leq d\leq 138$

Step-by-step explanation:

Let

d -----> the decibel level of the music

we know that

The absolute value of the difference of the decibel level of the music and its average, must be less than or equal to 28 decibels

so

The absolute value that represent this problem is

$\left|d-110\right|\le28$

Solve the absolute value

<em>First solution (positive)</em>

$+(d-110)\le28$

Adds 110 both sides

$d\le28+110$

$d\le138$

<em>Second solution (negative)</em>

$-(d-110)\le28$

Multiply by -1 both sides

$(d-110)\ge-28$

Adds 110 both sides

$d\ge-28+110$

$d\ge82$

therefore

The decibel range is

$82\leq d\leq 138$

8 0

4 years ago