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taurus [48]
2 years ago
11

In a game, if you roll a 6 on a 6-sided number cube, you lose a turn. (a) What is the probability that you roll a 6? Explain you

r reasoning. (b) What is the probability that you either roll a 6 or do not roll a 6? Explain your reasoning. (c) What is the probability that you don't roll a 6? Explain your reasoning
​
Mathematics
1 answer:
DiKsa [7]2 years ago
6 0
A) 1/6 six sides on the dice. B) 1 or 6/6 as everything is either a six or something else C) 5/6. Six sided dice six only makes up one of these sides so there are 5 others. Hope this helped
You might be interested in
What is the median of 16, 20, 20, 23, 25, 27, 29, 31, 31, and 32.
seraphim [82]

Answer:

27

Step-by-step explanation:

The madian is gis

5 0
3 years ago
The sum of 3 times a number and 7 is 25
hammer [34]

Mathematically written:

3 * x + 7 = 25

3x + 7 = 25

3x = 25 - 7

3x = 18

x = 18 / 3

x = 6



Proof:

3 * 6 + 7 = 25

18 + 7 = 25

25 = 25 → both sides of the equation are equal, our answer is correct



Notes:

A number - Is an unknown number, called a variable, which in this case is substituted by the letter x.





Hope it helped,




BioTeacher101


5 0
3 years ago
Read 2 more answers
X^2 + 3x - 4<br><br> please answer quickly! i will mark whoever answers first as brainliest &lt;3
vlabodo [156]

Answer:

(x-1) (x+4)

Step-by-step explanation:

Factor x^2+3x-4 using the AC method

4 0
2 years ago
Is the given pair a solution <br>y=-x -2; (2,-4)
nignag [31]
Yes
because
when x =2 then y = -(2) - 2 = -4

so (2,-4) is a solution

hope it helps
6 0
3 years ago
Suppose that a basketball player can score on a particular shot with probability .3. Use the central limit theorem to find the a
Rom4ik [11]

Answer:

(a) The probability that the number of successes is at most 5 is 0.1379.

(b) The probability that the number of successes is at most 5 is 0.1379.

(c) The probability that the number of successes is at most 5 is 0.1379.

(d) The probability that the number of successes is at most 11 is 0.9357.

→ All the exact probabilities are more than the approximated probability.

Step-by-step explanation:

Let <em>S</em> = a basketball player scores a shot.

The probability that a basketball player scores a shot is, P (S) = <em>p</em> = 0.30.

The number of sample selected is, <em>n</em> = 25.

The random variable S\sim Bin(25,0.30)

According to the central limit theorem if the sample taken from an unknown population is large then the sampling distribution of the sample proportion (\hat p) follows a normal distribution.

The mean of the the sampling distribution of the sample proportion is: E(\hat p)=p=0.30

The standard deviation of the the sampling distribution of the sample proportion is:

SD(\hat p)=\sqrt{\frac{ p(1- p)}{n} }=\sqrt{\frac{ 0.30(1-0.30)}{25} }=0.092

(a)

Compute the probability that the number of successes is at most 5 as follows:

The probability of 5 successes is: p=\frac{5}{25} =0.20

P(\hat p\leq 0.20)=P(\frac{\hat p-E(\hat p)}{SD(\hat p)}\leq  \frac{0.20-0.30}{0.092} )\\=P(Z\leq -1.087)\\=1-P(Z

**Use the standard normal table for probability.

Thus, the probability that the number of successes is at most 5 is 0.1379.

The exact probability that the number of successes is at most 5 is:

P(S\leq 5)={25\choose 5}(0.30)^{5}91-0.30)^{25-5}=0.1935

The exact probability is more than the approximated probability.

(b)

Compute the probability that the number of successes is at most 7 as follows:

The probability of 5 successes is: p=\frac{7}{25} =0.28

P(\hat p\leq 0.28)=P(\frac{\hat p-E(\hat p)}{SD(\hat p)}\leq  \frac{0.28-0.30}{0.092} )\\=P(Z\leq -0.2174)\\=1-P(Z

**Use the standard normal table for probability.

Thus, the probability that the number of successes is at most 7 is 0.4129.

The exact probability that the number of successes is at most 7 is:

P(S\leq 57)={25\choose 7}(0.30)^{7}91-0.30)^{25-7}=0.5118

The exact probability is more than the approximated probability.

(c)

Compute the probability that the number of successes is at most 9 as follows:

The probability of 5 successes is: p=\frac{9}{25} =0.36

P(\hat p\leq 0.36)=P(\frac{\hat p-E(\hat p)}{SD(\hat p)}\leq  \frac{0.36-0.30}{0.092} )\\=P(Z\leq 0.6522)\\=0.7422

**Use the standard normal table for probability.

Thus, the probability that the number of successes is at most 9 is 0.7422.

The exact probability that the number of successes is at most 9 is:

P(S\leq 9)={25\choose 9}(0.30)^{9}91-0.30)^{25-9}=0.8106

The exact probability is more than the approximated probability.

(d)

Compute the probability that the number of successes is at most 11 as follows:

The probability of 5 successes is: p=\frac{11}{25} =0.44

P(\hat p\leq 0.44)=P(\frac{\hat p-E(\hat p)}{SD(\hat p)}\leq  \frac{0.44-0.30}{0.092} )\\=P(Z\leq 1.522)\\=0.9357

**Use the standard normal table for probability.

Thus, the probability that the number of successes is at most 11 is 0.9357.

The exact probability that the number of successes is at most 11 is:

P(S\leq 11)={25\choose 11}(0.30)^{11}91-0.30)^{25-11}=0.9558

The exact probability is more than the approximated probability.

6 0
3 years ago
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