You have to put it in Y=MX+B form, so that mean you subtract the 2x in the first equation and move it to the other side of the equal sign so it will look like this Y=2X+5 and for the second equation you do the same thing and thats your answer
The product of (x1)^2 is 20
Make x the subject
2x = -3y + 1
5x = -2y -3
now times the answers to get the lcd
(2x = -3y + 1) x 5
10x = -15y + 5
(5x = -2y -3) 2
10x = -4y -6
now that they are equal to the same number:
-15y + 5 = -4y -6
-15y + 4y = -6 -5
-11y = -11
y = 1
now to find x we substitute y
2x = -3y + 1
2x = -3(1) + 1
2x = -3 + 1
2x = -2
x = -1
Answer:
final answer:
y-1= 3x_6
To solve our given problem, we must find the equation of the tangent line of the function f(x)=(x−1)3, at x=2.
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B is the correct answer im pretty sure
