<em>x</em> ^2 + <em>y</em> ^2 = 9 => <em>y</em> = <em>y(x)</em> = ± √(9 - <em>x</em> ^2)
Each cross section would be a square with side length equal to the vertical distance between the upper and lower semicircles defined by <em>y(x)</em>, which is
√(9 - <em>x</em> ^2) - (- √(9 - <em>x</em> ^2)) = 2 √(9 - <em>x</em> ^2)
The area of each square section is the square of this length,
(2 √(9 - <em>x</em> ^2)) = 4 (9 - <em>x</em> ^2) = 36 - 4<em>x</em> ^2
We get the whole solid for -3 ≤ <em>x</em> ≤ 3, so integrating gives a volume of
Answer:
Below.
Step-by-step explanation:
325/18
= 18.055... minutes
= 18 minutes to nearest minute.
the required algebraic expression is: 
Step-by-step explanation:
We need to write the algebraic expression of the sum of a number z divided by three and the number
Let the number be z
a number z divided by three: 
the sum of a number z divided by three and the number:
So, the required algebraic expression is:
Keywords: Algebraic expression
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The length of the rope with which the horse is tied becomes the radius of the circular area.
Length of rope = 5 m
Area within which the horse can graze
= pi * r^2 = 3.14 * 5 = 15.7 m^2
Area of the grassland at the Centre of which the horse is tied = 3.14 * 25
= 78.5 m^2
Area in which the horse cannot graze
= Area of grassland - Area in which the horse can graze
= 78.5 - 15.7
= 61.8 m^2
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<span> 3 7 lol more or less</span>
