Answer:
Step-by-step explanation:
When the coefficients don't lend themselves to solution by substitution or elimination, then Cramer's Rule can be useful. It tells you the solutions to
are ...
- ∆ = bd -ea
- x = (bf -ec)/∆
- y = (cd -fa)/∆
Using that rule here, we find ...
∆ = 5·3 -6·2 = 3
a = (5·54 -6·41)/3 = 5·18 -2·41 = 90 -82 = 8
s = (41·3 -54·2)/3 = 41 -18·2 = 5
This math can be performed in your head, which is the intent of formulating the rule in this way.
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Similarly, if you expect the solutions to be small integers (as here), then graphing is another viable solution method.
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<em>Comment on the question</em>
We're sad to see than only 16 tickets were sold to the two performances by the symphonic band.
Answer:
- Part A: The price of fuel A is decreasing by 12% per month.
- Part B: Fuel A recorded a greater percentage change in price over the previous month.
Explanation:
<u>Part A:</u>
The function 
calculates the price of fuel A each month by multiplying the price of the month before by 0.88.
Month price, f(x)
1 2.27 (0.88) = 1.9976 ≈ 2.00
2 2.27(0.88)² = 1.59808 ≈ 1.60
3 2.27(0.88)³ = 1.46063 ≈ 1.46
Then, the price of fuel A is decreasing.
The percentage per month is (1 - 0.88) × 100 = 12%, i.e. the price decreasing by 12% per month.
<u>Part B.</u>
<u>Table:</u>
m price, g(m)
1 3.44
2 3.30
3 3.17
4 3.04
To find if the function decreases with a constant ration divide each pair con consecutive prices:
- ratio = 3.30 / 3. 44 = 0.959 ≈ 0.96
- ratio = 3.17 / 3.30 = 0.960 ≈ 0.96
- ratio = 3.04 / 3.17 = 0.959 ≈ 0.96
Thus, the price of fuel B is decreasing by (1 - 0.96) × 100 =4%.
Hence, the fuel A recorded a greater percentage change in price over the previous month.
The equation is y=-5x + 20, x being the hours that go by after 5pm.
Answer:
7 & 8
Step-by-step explanation:
= 7.7459666924148337703585307995648
Therefore, it lies between the whole numbers 7 & 8.
Hope this helps :)
Answer:
The number of half-page advertisements is 4.
The number of Full-page advertisements is 11.
Step-by-step explanation:
According to the Question,
- Given, An advertising company charges $60 per half-page advertisement and $100 per full-page advertisement. Michael has a budget of $1340 to purchase 15 advertisements.
Let, 'x' be the number of half-page advertisements and 'y' be the number of full-page advertisements.
- Thus, 60x + 100y is the money charged, and given that he has a budget of $ 1340.
60x + 100y = 1340
- And, the number of advertisements is 15. So, the other equation is
x + y = 15
Now, We have Two Equations,
60x + 100y = 1340 and x + y = 15
- the solution of the system is Put x=(15-y) in Equation 60x + 100y = 1340
60 (15-y) + 100y = 1340
900 - 60y + 100y = 1340
40y = 1340 - 900
40y = 440
y = 440/40
y = 11 So, For x = 15 - y ⇒ 15-11 ⇒ x=4 .
- Thus, the number of half-page advertisements is 4 and The number of Full-page advertisements is 11 .
