Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
Answer:
.85%
Step-by-step explanation:
You add up all the students who have an A whether they are male or female. 3 + 17 = 20. You have 17 males right? Divide 17 by 20 to get .85
In order to write
as a percentage, we must first convert the fraction into a decimal. We can do that simply by dividing.
35 / 20 = 1.75
In order to convert a fraction to a decimal, we must multiply it by 100
1.75 * 100 = 175%
as a percentage is 175%.
Hope that helped =)
Answer:
47°
Step-by-step explanation:
Given that m<NLO = 41°, and m<NLM = 88°, according to angle addition postulate, m<OLM + m<NLO = m<NLM
Therefore, subtracting m<NLO from both sides will give us:
m<OLM = m<NLM - m<NLO
m<OLM = 88° - 41°
m<OLM = 47°
