The minimum surface area that such a box can have is 380 square
<h3>How to determine the minimum surface area such a box can have?</h3>
Represent the base length with x and the bwith h.
So, the volume is
V = x^2h
This gives
x^2h = 500
Make h the subject
h = 500/x^2
The surface area is
S = 2(x^2 + 2xh)
Expand
S = 2x^2 + 4xh
Substitute h = 500/x^2
S = 2x^2 + 4x * 500/x^2
Evaluate
S = 2x^2 + 2000/x
Differentiate
S' = 4x - 2000/x^2
Set the equation to 0
4x - 2000/x^2 = 0
Multiply through by x^2
4x^3 - 2000 = 0
This gives
4x^3= 2000
Divide by 4
x^3 = 500
Take the cube root
x = 7.94
Substitute x = 7.94 in S = 2x^2 + 2000/x
S = 2 * 7.94^2 + 2000/7.94
Evaluate
S = 380
Hence, the minimum surface area that such a box can have is 380 square
Read more about surface area at
brainly.com/question/76387
#SPJ1
I don't why you put -+ but I will go ahead and assume that it is -2.
4-+6
I think it is saying 4 - positive 6 but I'm guessing.
67593 increased bye 10430 is 78,023
A^2 + b^2 = c^2
a^2 + 7^2 = 11^2
49= 121
121 - 49 = 72
Square root(72) = 8.49
or you can just keep the square root symbol with 72 under it
Answer: Ethan will have to spend 2 hours reading if 14 pages are left to read
Step-by-step explanation:
Given the equation
P=-30h+74
where p =number of pages left to read and
h= the number of hours he has spent reading
Therefore , if Ethan has 14 pages left to read, then the number of hours Ethan will have to read will be
P=-30h+74
14= -30h + 74
30h= 74-14
30h= 60
h = 60/30
h =2 hours
Ethan will have to spend 2 hours reading if 14 pages are left to read
