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3 years ago

What is the slope of the line that passes through the points (3, 2) and (-1,-4)? m=

Mathematics

2 answers:

german3 years ago

5 0

Answer:

3/2

Step-by-step explanation:We know that,

Slope of the straight line passing through the points (x1,y1) and (x2,y2) is

m=y2-y1/x2-x1

Here,

Given, x1= 3,x2= 1

and y1= 2,y2= -4

so, the slope of the straight line is,

m= -4-2/-1-3

=3/2

ad-work [718]3 years ago

3 0

The answer is 3/2

Explanation: the formula is y-y /x-x
So it’ll be 2-(-4) /3-(-1) which will give 6 /4 and that simplifies will give 2/ 3

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The value of x in the equation 4(x + 5) = 9x + 4x − 34 is 6 after solving and applying properties.

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It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

We have equation:

4(x + 5) = 9x + 4x − 34 (Given)

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Answer:

$\boxed{\sf \ \ \ \dfrac{18}{(x-7)(x+12)(x+30)} \ \ \ }$

Step-by-step explanation:

hello,

first of all we will study the quadratic expressions

we can write that, (the different answers provide good clues :-) )

$x^2+5x-84=(x-7)(x+12)$

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$x^2+23x-210=(x-7)(x+30)$

so first of all as we cannot divide by 0 we need to take x different from 7, -12 and -30 and then we can write

$\dfrac{1}{x^2+5x-48}-\dfrac{1}{x^2+23x-210}=\dfrac{1}{(x-7)(x+12)}-\dfrac{1}{(x-7)(x+30)}\\\\=\dfrac{(x+30) -(x+12)}{(x-7)(x+12)(x+30)}=\dfrac{x+30-x-12}{(x-7)(x+12)(x+30)}\\\\=\dfrac{18}{(x-7)(x+12)(x+30)}$

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