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Blizzard [7]
3 years ago
7

Gardener has 780 plants. He wants to plant there in such a way that the number of rows and the numbers of columns remains same.

Find the minimum number of plants need more for this.​
Mathematics
1 answer:
AleksAgata [21]3 years ago
5 0

Answer:

<em>Gardener will need 4 more plants.</em>

Step-by-step explanation:

Gardener has 780 plants and wants to plant them in an array of n rows and n columns.

The number of plants needed to do that is:

n*n=n^2

He actually has 780 plants, thus it should occur:

n^2=780

Taking the square root:

n=27.9

Since n needs to be an integer, we round up n to get

n=28

But 28^2=784, 4 more than the actual number of plants, thus:

Gardener will need 4 more plants.

Note: There are other possible results for n. If we set n=29, then n^2=841 and Gardener would need 841-780=61 more plants, but the question asked for the minimum number of plants.

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The solution to given system of equations is (x, y) = (2, -1)

<em><u>Solution:</u></em>

Given system of equations are:

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We can solve the above system of equations by elimination method

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<em><u>Check the answer:</u></em>

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