Answer:
Proportional.
Step-by-step explanation:
Find the cross products. If they are same, then they are proportional.
Cross multiply,
1.2 * 4 .5 = 3*1.8
5.40 = 5.4
So, they are proportional.
Or
Multiply the numerator and denominator of 1.2/3 by 1.5
From this we come to know they are proportional
Or
1.2 : 3 :: 1.8 : 4.5
Product of means = 3*1.8 = 5.4
Product of extremes = 1.2*4.5 = 5.4
Product of means = product of extremes. So, they are proportional.
Answer:
{x = 2 , y = -2
Step-by-step explanation:
Solve the following system:
{y = 4 - 3 x | (equation 1)
{y = x/2 - 3 | (equation 2)
Express the system in standard form:
{3 x + y = 4 | (equation 1)
{-x/2 + y = -3 | (equation 2)
Add 1/6 × (equation 1) to equation 2:
{3 x + y = 4 | (equation 1)
{0 x+(7 y)/6 = (-7)/3 | (equation 2)
Multiply equation 2 by 6/7:
{3 x + y = 4 | (equation 1)
{0 x+y = -2 | (equation 2)
Subtract equation 2 from equation 1:
{3 x+0 y = 6 | (equation 1)
{0 x+y = -2 | (equation 2)
Divide equation 1 by 3:
{x+0 y = 2 | (equation 1)
{0 x+y = -2 | (equation 2)
Collect results:
Answer: {x = 2 , y = -2
Answer:
39
Step-by-step explanation:
Let the number be x.
The quotient of x and 3 is 13.
x/3 = 13
Multiply both sides by 3.
x = 13 × 3
x = 39
Answer:
y = 4x -3
Step-by-step explanation:
Answer:
The test was not statistically significant because if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 21% of the time.
Step-by-step explanation:
This is the right answer,since this result is only observed 21% of the time, so in general it's not significant, so the first 2 are eliminated. The 2 x 0.21 doesn't matter since, the percent is 21% not 42%, so it doesn't even matter. The last question we eliminate is:"The test was not statistically significant because if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 79% of the time" 79% of the time is a pretty good amount to say it's significant, but it only says 21% of the time.So, it leaves us with:The test was not statistically significant because if the null hypothesis is true, one could expect to get a test statistic at least as extreme as that observed 21% of the time.
Hope this helps lol (: is this a psat or somethin?
