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yuradex [85]
3 years ago
6

A ball is thrown in air and it’s height, h(t) in feet, at any time, t in seconds, is represented by the equation h(t) =-t^2+7t.

When is the ball higher than 10 feet off the ground?
Mathematics
1 answer:
Lisa [10]3 years ago
4 0

Answer:

The ball is higher than 10 feet off the ground when the time is between 2 to 5 seconds

Step-by-step explanation:

In the above question, we are given the equation:

h(t) =-t²+7t.

We are asked to find the time (t) when the ball will be higher than 10 feet.

h(t) = height = 10 feet.

So we have:

10 = -t² + 7t

t² - 7t + 10 = 0

We have a quadratic equation hence we factorise.

t² - 5t - 2t + 10 = 0

(t² - 5t) +(2t - 10)= 0

t(t - 5) + 2 (t - 5) = 0

(t - 2) (t - 5) = 0

t - 2 = 0, t = 2

t - 5 = 0, t = 5

t = 5 and t = 2

Therefore, the ball is higher than 10 feet off the ground when the time is between 2 to 5 seconds.

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Reason 3: Definition of Parallelogram
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------------------------------------------------------

Explanations:

Explanation for Reason 3: A parallelogram, by definition, has opposite sides that are parallel. It's built into the name more or less. Sides AB and CD are opposite one another in the parallelogram so they are parallel segments

Explanation for Reason 4: Angle ABD is congruent to angle CDB because they are alternate interior angles. They are on the inside of the "train tracks" that are formed by AB and CD. They lay on opposite sides of the transversal BD

Explanation for Reason 5: Any segment is congruent to itself; ie, the same length

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