All categories

3 years ago

X(x+2) + y (x + 2) - 5(x + 2) factor

Mathematics

2 answers:

Tanzania [10]3 years ago

8 0

First of expand the equation

X^2+2x+yx+2y-5x-10

X^2+yx-3x+2y-10

Final answer=

X(x+y-3)+2(y-5)

Andrej [43]3 years ago

7 0

Answer:

x² + xy - 3x + 2y - 10

Step-by-step explanation:

x(x + 2) + y(x + 2) - 5(x + 2)

x² + 2x + y(x + 2) - 5(x + 2)

x² + 2x + xy + 2y - 5(x + 2)

x² + 2x + xy + 2y - 5x - 10

x² - 3x + xy + 2y - 10

x² + xy - 3x + 2y - 10

You might be interested in

Any chance with 23-25?

iogann1982 [59]

This math answer is -2

4 0

4 years ago

Janine has 3 3/4 cup of flour. She uses 1/3 of the flour to make pancakes.How many cups of flour did she use?

KATRIN_1 [288]

1 1/4 cups of flour was used

8 0

4 years ago

Read 2 more answers

In a bowl of marbles, there are 10 red ones, 6 blue ones, and green onesa marble is chosen at random from the bowl, find P(red o

Zolol [24]

Answer:

It is most-likely a red marble

Step-by-step explanation:

I say it is a red marble because as you said, there are 10 red marbles and 6 blue ones and since there are 4 more red marbles, there is a higher perchentage of it being a red marble . (I hope i answered your question)

6 0

3 years ago

Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1

belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

$F(x) = \int\limits^a_b {f(x)} \, dx$

By using integration formula

$\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c$

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

$\int\limits^6_^-6} (x^{5} + 8 x^{4} + 2 x^{2} + 5 x + 15) )dx$

On integration , we get

= $(\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}$

$F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)$

= $(\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))$