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3 years ago

It is not possible to solve percent problems using proportions. True or False

2 answers:

8 0

Thank you posting your question on Brainly. I hope my answer is satisfactory to you.

The answer is: FALSE
It is possible to solve percent problems using proportions.

Hope this helps!

jekas [21]3 years ago

3 0

False you can use proportions to solve percent problems

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0.03 x 5=<br><br><br> How is this solved?

Nadya [2.5K]

Answer: 0.15

Step-by-step explanation:

Multiply 0.03 by 5.

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2 years ago

Read 2 more answers

What are the answers for both of those if you get it right I’ll also give you brainliest answer comment

tangare [24]

Answer:

answer 1, 135

Step-by-step explanation:

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3 years ago

There are 5 red balls, 4 blue balls, 6 yellow balls and 10 green balls in a box,

lys-0071 [83]

According to given information there are :

5 red balls

4 blue balls

6 yellow balls

10 green balls

<h3>1. what is the probability that the ball chosen is red ?</h3>

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{total \: red \: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{5}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{5}{25}$

$\qquad \sf \dashrightarrow \: p(red) = \dfrac{1}{5}$

<h3>2. what is the probability that the ball chosen is blue ?</h3>

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{total \: blue \: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{4}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(blue) = \dfrac{4}{25}$

<h3>3. what is the probability that the ball chosen is yellow ?</h3>

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{total \: yellow\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{6}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(yellow) = \dfrac{6}{25}$

<h3>4. what is the probability that the ball chosen is green ?</h3>

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{total \: green\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{10}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{10}{25}$

$\qquad \sf \dashrightarrow \: p(green) = \dfrac{2}{5}$

<h3>5. what is the probability that the ball chosen is not green ?</h3>

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{total \: non \: green\: balls}{total \: balls}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{5 + 4 + 6}{5 + 4 + 6 + 10}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{15}{25}$

$\qquad \sf \dashrightarrow \: p(not \: green) = \dfrac{3}{5}$

3 0

1 year ago

Please help me with this question <br><br> image attached

Mumz [18]

Answer: (D) 9

<u>Step-by-step explanation:</u>

This is an isosceles triangle. Since the legs are congruent, then the base angles are congruent.

9x + 3 = 84

9x = 81

x = 9

8 0

3 years ago

Rationalize the denominator, then simplify 10/sqrt2

kupik [55]

Answer:

$5\sqrt{2}$

Step-by-step explanation:

To rationalize the denominator, you need to multiply the numerator and denominator by the radical in the denominator (aka. a factor of 1):

$\frac{10}{\sqrt{2}}$

$\frac{10}{\sqrt{2}}*\frac{\sqrt{2}}{\sqrt{2}}$

$\frac{10\sqrt{2}}{2}$

$5\sqrt{2}$

6 0

2 years ago