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madreJ [45]
3 years ago
11

Need help solving these two vector problems.

Mathematics
1 answer:
jonny [76]3 years ago
4 0
<h3>Answer:</h3>

see below

<h3>Step-by-step explanation:</h3>

Here, we'll use an ordered pair <a, b> to represent each vector's two components. The rules are ...

  • multiplying a vector by a scalar multiplies each component by that scalar
  • multiplying a vector by a scalar multiplies its magnitude by the magnitude of the scalar
  • the magnitude of a vector is the square root of the sum of the squares of its components
<h2>1.</h2>

For A = <2.5, -3.5>, |A| = √(2.5²+(-3.5)²) = √18.5 ≈ 4.30

  • 2A = <5, -7>; |2A| = 8.60
  • -2A = <-5, 7>; |-2A| = 8.60
  • A/2 = <1.25, -1.75>; |A/2| = 2.15

_____

<h2>2.</h2>

A = |A|<cos(43.9°), sin(43.9°)>

B = |B|<cos(154.8°), sin(154.8°)>

C = <0, -25.8>

The sum being zero gives rise to 2 equations in 2 unknowns.

  |A|cos(43.9°) +|B|cos(154.8°) = 0

  |A|sin(43.9°) +|B|sin(154.8°) = 25.8

Using Cramer's rule to find the solution, we get ...

  |A| = 25.8cos(154.8°)/(cos(154.8°)sin(43.9°) -sin(154.8°)cos(43.9°))

  |A| = 25.8cos(154.8°)/sin(43.9° -154.8°)

  |A| ≈ 24.9887

  |B| = -25.8cos(43.9°)/sin(-110.9°)

  |B| ≈ 19.8995

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