(a)
The inverse is when you swap the variables and solve for y.
g(t) = 2t - 1 (Note: g(t) represents y)
rewrite as: y = 2t - 1
swap the variables: t = 2y - 1
solve for y: t + 1 = 2y

= y
Answer for (a):
=
(b)
Same steps as part (a) above:
h(t) = 4t + 3
rewrite as: y = 4t + 3
swap the variables: t = 4y + 3
solve for y:
Answer for (b):
= 
(c)

replace all t's in the

equation with

=

=

=

=
Answer for (c):
= 
(d)
h(g(t)) = h(2t - 1) = 4(2t - 1) + 3 = 8t - 4 + 3 = 8t - 1
Answer for (d): h(g(t)) = 8t - 1
(e)
h(g(t)) = 8t - 1
y = 8 t - 1
t = 8y - 1
t + 1 = 8y

= y
Answer for (e): inverse of h(g(t)) =
It would be the 2nd one 35 divide by 7=5
Prob of selected students times prob of selecting boys times prob of selecting 3 boys
total students = 15b + 30g = 45 students
1. 10s/45t = 0.22
2. 15b/45t = 0.33
3. 3b/15b = 0.2
0.22×0.33×0.2=0.0148
1.48%
I'm not sure 100%... double check answer please
Answer:
..........
Step-by-step explanation:
C is the answer. By only looking at the domain (the stuff on the right in the functions), you can see that the first equation has a hole at x=2, meaning it does not have a value here at x=2. When x<2, there are values for the 1st function. When x>2, there are values for the second function, as well as when x=2