0.236 gm of Metal X reacts with O2 forming 0.436 of the compound X2O3 what is the gram atomic mass of x?

A nonvolatile solute is dissolved in benzene so that it has a mole fraction of 0.139. What is the vapor pressure of the solution

lapo4ka [179]

Answer:

The vapor pressure of the solution is 3.69 torr

Explanation:

Step 1: Data given

Mole fraction of benzene in the solution = 0.139

P° of benzene is 26.5 torr

Step 2: Calculate the vapor pressure of the solution

Psolution = Xbenzene * P°benzene

⇒with Psolution = the vapor pressure of the solution

⇒with Xbenzene = the mole fraction of benzene = 0.139

⇒with P°benzene = the vapor pressure of pure benzene = 26.5 torr

Psolution = 0.139 * 26.5 torr

Psolution = 3.69 torr

The vapor pressure of the solution is 3.69 torr

7 0

4 years ago

What three parts make up an atom?

MissTica

The nucleus of an atom is made up of protons and neutrons. Then electrons circle around the nucleus.

Answer:

Proton, Neutron, Electron

8 0

4 years ago

Read 2 more answers

What did Bohr conclude about the atom after observing emission spectrum lines a. Electrons can exist in any energy state but hav

cupoosta [38]

Answer:

Option c: Possible electron energy states are quantized within an atom.

Explanation:

The Bohr's Model of the hydrogen atom consisted of the movements of the electrons around the positively-charged nucleus in circular orbits that have a certain energy state. The energy of that orbit is given by:

$E_{n} = - \frac{Rhc}{n^{2}}$

<em>Where:</em>

E(n): is the energy of an electron in a particular orbit

R: is the Rydberg constant

h: is the Plank constant

c: is the speed of light

n: is a positive integer which corresponds to the number of the orbit

The ground state energy of a electron in the hydrogen atom is equal to -13,6 eV.

Bohr's Model aims to propose that the electron is restrictedly to occupy a certain region in the atom.

Therefore, the conclusion of Bohr after observing emission spectrum lines is that "possible electron energy states are quantized within an atom", so the correct option is c.

I hope it helps you!

7 0

4 years ago

Which topic is commonly used to explain activation energy and how chemical reactions happen?

love history [14]

Kinetics is the topic generally used to explain

7 0

3 years ago

A) Calculate the average density of the following object (assume it is a perfect sphere). SHOW ALL YOUR WORK (formulas used, num

-BARSIC- [3]

Answers:

A) 2040 kg/m³; B) 58 600 km

Explanation:

A) Density

$V = \frac{ 4}{3 }\pi r^{3} = \frac{ 4}{3 }\pi\times (\text{1150 km})^{3} = 6.37 \times 10^{9} \text{ km}^{3}$

$\text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{1.3\times 10^{22} \text{ kg} }{6.37 \times 10^{9} \text{ km}^{3}}\times (\frac{\text{1 km}}{\text{1000 m}})^{3} = \text{2040 kg/m}^{3}$

<em>B) Radius</em>

$\text{Volume} = \frac{\text{mass}}{\text{density}} = \frac{5.68\times 10^{26} \text{ kg} }{687 \text{ kg/m}^{3} }= 8.268 \times 10^{23} \text{ m}^{3}$

$V = \frac{ 4}{3 }\pi r^{3}$

$r^{3} = \frac{3V }{4 \pi }\$

$r= \sqrt [3]{ \frac{3V }{4 \pi } }$

$r= \sqrt [3]{ \frac{3\times 8.268 \times 10^{23} \text{ m}^{3}}{4 \pi } }= \sqrt [3]{ 1.974 \times 10^{23} \text{ m}^{3}}= 5.82 \times 10^{7} \text{ m}=\text{58 200 km}$

3 0

3 years ago

0.236 gm of Metal X reacts with O2 forming 0.436 of the compound X2O3 what is the gram atomic mass of x?​

0.236 gm of Metal X reacts with O2 forming 0.436 of the compound X2O3 what is the gram atomic mass of x?