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slega [8]
3 years ago
15

Glycerol is a syrupy liquid often used in cosmetics and soaps. A 3.25-L sample of pure glycerol has a mass of 4.10 x 10 g.

Chemistry
1 answer:
Pavel [41]3 years ago
8 0

Explanation:

It is known that density is the amount of mass present in liter of solution or substance.

Mathematically,      Density = \frac{mass}{volume}

It is given that volume is 3.25 L and mass is 4.10 \times 10^{3} g. Hence, calculate the density of glycerol as follows.

                     Density = \frac{mass}{volume}

                                   = \frac{4.10 \times 10^{3} g}{3.25 L}

                                    = 1.26 \times 10^{3} g/L

As, 1 L = 1000 cm^{3}.

So,           1.26 \times 10^{3} g/L \times \frac{1000 cm^{3}}{1 L}

                 = 1260 \times 10^{6} g/cm^{3}    

Thus, we can conclude that the density of glycerol is 1260 \times 10^{6} g/cm^{3}.

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Answer:

<u>84.00 kPa = 630.084 torr</u>

Formula for kPa to torr: For an approximate result, multiply the pressure value by 7.501. <em><u>84* 7.501</u></em>

<u>84.00 kPa = 0.831683168 atm</u>

Formula for kPa to atm: for an approximate result, divide the pressure value by 101. <em><u>84/101</u></em>

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3 years ago
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Addition of  boiled, deionized water to the titrating flask to wash the wall of the erlenmeyer flask and the buret tip will have no effect on the Ksp value of ca(oh)2.

There will be no effect on the Ksp value as boiled deionised water is not able to alter the number of hydronium and hydroxide ions. As no change in the ions happen so there will be no change in Ksp value. The equilibrium constant for a solid material dissolving in an aqueous solution is the solubility product constant, Ksp. It stands for the degree of solute dissolution in solution. A substance's Ksp value increases with how soluble it is.

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sunlimation is when a solid goes to a gas thats all i can awnser i havent got that far in chemistry yet.

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Answer: B

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