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slega [8]
3 years ago
15

Glycerol is a syrupy liquid often used in cosmetics and soaps. A 3.25-L sample of pure glycerol has a mass of 4.10 x 10 g.

Chemistry
1 answer:
Pavel [41]3 years ago
8 0

Explanation:

It is known that density is the amount of mass present in liter of solution or substance.

Mathematically,      Density = \frac{mass}{volume}

It is given that volume is 3.25 L and mass is 4.10 \times 10^{3} g. Hence, calculate the density of glycerol as follows.

                     Density = \frac{mass}{volume}

                                   = \frac{4.10 \times 10^{3} g}{3.25 L}

                                    = 1.26 \times 10^{3} g/L

As, 1 L = 1000 cm^{3}.

So,           1.26 \times 10^{3} g/L \times \frac{1000 cm^{3}}{1 L}

                 = 1260 \times 10^{6} g/cm^{3}    

Thus, we can conclude that the density of glycerol is 1260 \times 10^{6} g/cm^{3}.

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In the essay box, compose a scientific report which includes your observations, data, and conclusions. The following questions s
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1. It depends what type of method you are using. if it is Height x Width x Length then it will not work for an irregular shape because it has extra pieces that would not be included.

2. The second method would work for both regular and irregular shapes because you would have to know or find out the volume of the regular shape to get the volume for the irregular shape.

3. It also depends on what you are doing, if you are doing a regular shape then use the first method, if it's an irregular shape then use the second method, if you do the maths correctly both should give you an accurate answer for what you want to achieve.

4. No, because the sugar would dissolve.

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All the answers for you!

4 0
3 years ago
EXPERIMENT: DETERMINING VOLUME
Tanzania [10]

Explanation:

(Ques- A) Why does the first method for determining volume work only for a regular-shaped object?

<u>(Ans- A)</u> <em>Because the method requires precise dimensions of objects for result, which is not possible for irregular shaped objects.</em>

(Ques - B) Will the second method for determining volume work for any object or just an odd-shaped one? Why?

<u>(Ans-B)</u> <em>It will work for both regular and irregular shaped objects since both displace equal volumes of water.</em>

(Ques - C) Is one method of measurement more accurate than the other? Why or why not?

<u>(Ans-C)</u> <em>Both are pretty accurate, with some experimental errors which may creep in accidentally. </em>

(Ques- D) Would the displacement method of measurement work for a cube of sugar? What about a cork? Why?

<u>(Ans - D)</u> <em>No, the method would not work because sugar being soluble, will dissolve in water. </em>

<em>No, the method would not work because sugar being soluble, will dissolve in water. Cork is less dense than water so floats on it, with only part of it submerged in water, resulting in displacement of less volume of water than actual volume of Cork.</em>

(Ques-E) What did you find out from this investigation? Be thoughtful in your answer.

<u>(Ans- E)</u> <em>I learnt about determining volume of different objects from this investigation. </em>(Sorry, I know its not a very thoughtful answer)

7 0
3 years ago
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