Percent yield = (Actual Yield/ Theoretical Yield) x 100
Given, Actual Yield of silver = 410 grams
Given, mass of copper = 127 g
Atomic mass of copper = 63.546 amu
Formula: Moles = mass / atomic mass
Moles of copper = 127 g/ 63.546 amu = 1.998 mol
Based on the given balanced chemical reaction, the molar ratio between Cu: Ag is 1:2
So 1.998 mol of copper should yield (2 mol Ag/ 1 mol Cu) x 1.998 mol of Cu = 3.996 mol
Calculated mol of Ag = 3.996 mol
Atomic mass of silver = 107.8682 amu
Mass of silver = moles x atomic mass = 3.996 mol x 107.8682 amu = 431 g
Based on the math, the theoretical yield = 431 g
Percent yield of silver = (410g/431g) x 100 = 95. 13%
The answer is 95. 13%
