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3 years ago

14

Jocelyn estimates that a piece of wood measures 5.5 cm. If it actually measures 5.62 cm, what is the percent error of Jocelyn’s

estimate?
A. 2.13%
B. 2.18%
C. 12%
D. 46.83%

1 answer:

nataly862011 [7]3 years ago

5 0

Answer:

A

okay? Answer A

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The average weight of a newborn panda is 0.2, or 2/10 pound. Between what two integers is the weight of a newborn panda?

sweet-ann [11.9K]

Answer:

$\frac{2}{10}$ lies between 0 and 1.

Step-by-step explanation:

We must have in mind that given average weight of a newborn panda is a non-integer rational number, such that lies between two integer rational number. In other words, this number must satisfy the following condition:

$n < \frac{a}{b} < n +1$ , $n, a, b \in \mathbb{N}_{O}$

$\mathbb{N}_{O} = \mathbb{N}\,\cup\,{\{0\}}$

Which is now developed mathematically to deduce a useful expression to find integers:

1) $n < \frac{a}{b} < n +1$ Given

2) $n \cdot 1 < \frac{a}{b} < n\cdot 1 + 1$ Modulative property

3) $n \cdot (b\cdot b^{-1}) < a\cdot b^{-1} < n \cdot (b\cdot b^{-1}) + b\cdot b^{-1}$ Existence of Multiplicative inverse/Definition of division.

4) $(n\cdot b)\cdot b^{-1} < a\cdot b^{-1}< [(n+1)\cdot b] \cdot b^{-1}$ Commutative, Associative and Distributive properties.

5) $n\cdot b < a < (n+1)\cdot b$ Compatibility with Multiplication/Existence of Multiplicative Inverse/Modulative Property/Result.

If we know that $a = 2$ and $b = 10$ , the following inequation is formed:

$10\cdot n < 2 < 10\cdot (n+1)$

It is quite evident to conclude that $\frac{2}{10}$ lies between 0 and 1.

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3 years ago

Suppose we have three urns, namely, A B and C. A has 3 black balls and 7 white balls. B has 7 black balls and 13 white balls. C

professor190 [17]

Answer:

a. 11/25

b. 11/25

Step-by-step explanation:

We proceed as follows;

From the question, we have the following information;

Three urns A, B and C contains ( 3 black balls 7 white balls), (7 black balls and 13 white balls) and (12 black balls and 8 white balls) respectively.

Now,

Since events of choosing urn A, B and C are denoted by Ai , i=1, 2, 3

Then , P(A1 + P(A2) +P(A3) =1 ....(1)

And P(A1):P(A2):P(A3) = 1: 2: 2 (given) ....(2)

Let P(A1) = x, then using equation (2)

P(A2) = 2x and P(A3) = 2x

(from the ratio given in the question)

Substituting these values in equation (1), we get

x+ 2x + 2x =1

Or 5x =1

Or x =1/5

So, P(A1) =x =1/5 , ....(3)

P(A2) = 2x= 2/5 and ....(4)

P(A3) = 2x= 2/5 ...(5)

Also urns A, B and C has total balls = 10, 20 , 20 respectively.

Now, if we choose one urn and then pick up 2 balls randomly then;

(a) Probability that the first ball is black

=P(A1)×P(Back ball from urn A) +P(A2)×P(Black ball from urn B) + P(A3)×P(Black ball from urn C)

= (1/5)×(3/10) + (2/5)×(7/20) + (2/5)×(12/20)

= (3/50) + (7/50) + (12/50)

=22/50

=11/25

(b) The Probability that the first ball is black given that the second ball is white is same as the probability that first ball is black (11/25). This is because the event of picking of first ball is independent of the event of picking of second ball.

Although the event picking of the second ball is dependent on the event of picking the first ball.

Hence, probability that the first ball is black given that the second ball is white is 11/25

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3 years ago

What’s the correct answer

Stels [109]

$a_n=a_{n-1}+7 \ \ \to \ \ d=7 \\ \\ a_n=a_1+d(n-1) \\ a_n=17+7(n-1) \\ a_n=17+7n-7 \\ a_n=7n+10$

The answer is B. a_n = 7n+10

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The school currently has 30 classrooms. With the addition, there will be 40 classrooms. What percentage of the current number of

stiv31 [10]

The answer is 34%
30+33%=39.9
So round up two 34%
I hope that is right but I think the answer is 34%

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Answer:

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Step-by-step explanation:

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2 years ago

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