Part 1We are given

. This can be rewritten as

.
Therefore, a=1, b=-18, c=0.
Using the quadratic formula

The values of x are
Part 2Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a
quadratic function. Part 3.The first equation is

.
The second equation is

.
We have

Factoring, we have

Equating both factors to zero.

When the value of x is 6, the value of y is

When the value of x is -3, the value of y is

Therefore, the solutions are (6,38) or (-3,11)
Answer:x^6/4
Step-by-step explanation:
Simplifying the steps
Answer:
(4, -3)
Step-by-step explanation:
<span>2.48030, its rounded tenths 2.5 hundreths 2.48 thousands 2.480 ten-thousands 2.4803 then </span>hundred-thousandth 2.48030
Answer:
Step-by-step explanation:
Let
be the greater number and
be the smaller number. We know that their difference is 15, so we have

Then, we have the following information: if we add twice the greater (2x) and 8 (2x+8), the result is 3 times the lesser (3y) minus four (3y-4). So, we have

So, we have the follwing system:

From the first equation, we can derive
, and substitute this expression in the second equation to get

Substitute this value for y in the first equation to get
