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2 years ago

Can someone please help me solve 91

Mathematics

2 answers:

sasho [114]2 years ago

8 0

3x^3+7x^2-20x=0 factor out x first

x(3x^2+7x-20)=0

x(3x^2+12x-5x-20)=0

x(3x(x+4)-5(x+4))=0

x(3x-5)(x+4)=0

x={-4, 0, 5/3}

Mashcka [7]2 years ago

5 0

$3x^3+7x^2-20x=0\\
x(3x^2+7x-20)=0\\
x(3x^2-5x+12x-20)=0\\
x(x(3x-5)+4(3x-5))=0\\
x(x+4)(3x-5)=0\\
x=0 \vee x=-4 \vee x=\dfrac{5}{3}$

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