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olga nikolaevna [1]
3 years ago
8

Can someone please help me solve 91

Mathematics
2 answers:
sasho [114]3 years ago
8 0
3x^3+7x^2-20x=0  factor out x first

x(3x^2+7x-20)=0

x(3x^2+12x-5x-20)=0

x(3x(x+4)-5(x+4))=0

x(3x-5)(x+4)=0

x={-4, 0, 5/3}
Mashcka [7]3 years ago
5 0
3x^3+7x^2-20x=0\\
x(3x^2+7x-20)=0\\
x(3x^2-5x+12x-20)=0\\
x(x(3x-5)+4(3x-5))=0\\
x(x+4)(3x-5)=0\\
x=0 \vee x=-4 \vee x=\dfrac{5}{3}
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