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Umnica [9.8K]
3 years ago
14

`y=2x+1` was a positive slope because...

Mathematics
1 answer:
Kobotan [32]3 years ago
6 0

Step-by-step explanation:

.....because the coefficient of x is 2, a positive number.

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Please answer correctly! I will mark you as Brainliest!
zheka24 [161]

Answer:

the height is 9.8 cm

Step-by-step explanation:

71.54 ÷ 7.3 = 9.8

6 0
3 years ago
Question:
prohojiy [21]
Let f(x) = p(x)/q(x), where p and q are polynomials and reduced to lowest terms. (If p and q have a common factor, then they contribute removable discontinuities ('holes').) 
Write this in cases: 
(i) If deg p(x) ≤ deg q(x), then f(x) is a proper rational function, and lim(x→ ±∞) f(x) = constant. 
If deg p(x) < deg q(x), then these limits equal 0, thus yielding the horizontal asymptote y = 0. 
If deg p(x) = deg q(x), then these limits equal a/b, where a and b are the leading coefficients of p(x) and q(x), respectively. Hence, we have the horizontal asymptote y = a/b. 
Note that there are no obliques asymptotes in this case. ------------- (ii) If deg p(x) > deg q(x), then f(x) is an improper rational function. 
By long division, we can write f(x) = g(x) + r(x)/q(x), where g(x) and r(x) are polynomials and deg r(x) < deg q(x). 
As in (i), note that lim(x→ ±∞) [f(x) - g(x)] = lim(x→ ±∞) r(x)/q(x) = 0. Hence, y = g(x) is an asymptote. (In particular, if deg g(x) = 1, then this is an oblique asymptote.) 
This time, note that there are no horizontal asymptotes. ------------------ In summary, the degrees of p(x) and q(x) control which kind of asymptote we have. 
I hope this helps!
4 0
3 years ago
Refer to the figure below to complete the following item.
Dmitrij [34]

Answer:

160

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Carson graphs the line y= -1/4 + 4. Then Riley's graphs the line perpendicular to the line Carson's line through the point (8,10
gizmo_the_mogwai [7]

Answer:

4/1 or 4

Step-by-step explanation:

when graphing perpendicular lines, the slopes are reciprocals of eachother

5 0
3 years ago
Tell whether the square root of .25 is rational or irrational. Explain.
artcher [175]
The square root of .25 is rational because it is a terminating decimal.
√(.25)=05
8 0
3 years ago
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