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raketka [301]
3 years ago
7

Find the equation of the line with slope 7 which goes through the point (-2,-9). Give your answer in slope intercept form y=mx+b

Mathematics
1 answer:
Sedbober [7]3 years ago
7 0

Answer:

I need the to solve dis question

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Given a cylinder with a volume of 350 cubic inches and height of 7 inches. Find B, the area of the base. Use 3.14 for pie
rusak2 [61]

UzusuxhzjaisuzAnswer:

Step-by-step explanation:

4 0
3 years ago
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The line that contains the point Q( 1, -2) and is parallel to the line whose equation is y - 4 = 2/3 (x - 3)
Musya8 [376]

Answer:

y + 2 = \frac{2}{3}(x - 1)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

y - 4 = \frac{2}{3}(x - 3) ← is in point- slope form

with slope m = \frac{2}{3}

Parallel lines have equal slopes, thus equation of parallel line

with m = \frac{2}{3} and (a, b) = Q(1, - 2) is

y - (- 2) = \frac{2}{3}(x - 1) , that is

y + 2 = \frac{2}{3}(x - 1)

7 0
3 years ago
If 1900 square centimeters of material are available to make a box with a square base and an open top, find the largest possible
Evgen [1.6K]

Answer:

Volume = 7969 cubic centimeter

Step-by-step explanation:

Let the length of each side of the base of the box  be A and the height of the box be H.

Area of material required to make the box  is equal to  is A^2 + 4*A*H.

A^2 + 4*A*H = 1900

 Rearranging the above equation, we get -  

`H = \frac{(1900 - A^2)}{(4*A)}

Volume of box is equal to product of base area of box and the height of the box -  

V = A*A* H

Substituting the given area we get -

\frac{A^2*(1900 - A^2)}{4A} = \frac{(1900*A - A^3)}{4}

For maximum volume

\frac{dV}{dA} =0

\frac{ 1900}{4} - \frac{3*A^2}{4} = 0

A^2 = \frac{1900}{3}

Volume of the box

= \frac{\frac{1900}{3}*(1900 - \frac{1900}{3}) }{4 * \sqrt{\frac{1900}{3} } }

= 7969 cubic centimeter

3 0
3 years ago
Help this is due tomorrow but she didn’t teach us how.
mario62 [17]

Answer:

  see below for drawings and description

Step-by-step explanation:

For geometry problems involving translation, rotation, and reflection—transformations that change location, but not size ("rigid" transformations)—it might be helpful for you to trace the image onto tracing paper or clear plastic so that you can manipulate it in the desired way. Eventually, you'll be able to do this mentally, without the aid of a physical object to play with.

For the images attached here, I copied the triangle onto a piece of clear plastic so I could move it to the desired positions. The result was photographed for your pleasure.

__

a. Translation means the image is moved without changing its orientation or dimensions. You are asked to copy the triangle so that the upper left vertex is moved to what is now point E. See the first attachment.

__

b. Reflection means the points are copied to the same distance on the other side of the point or line of reflection. Just as an object held to a mirror has its reflection also at the mirror, any points on the line of reflection do not move. Reflection flips the image over. See the second attachment.

__

c. Rotation about point D means point D stays where it is. The angle of rotation is the same as the angle at D, so the line DE gets rotated until it aligns with the line DF. The rest of the triangle maintains its shape. See the third attachment.

8 0
3 years ago
HELPPPPPP MEEEEE<br><br> y=6x-1<br><br> and -2x-3y=-2 <br><br><br> USING SUBSTITUTION
bazaltina [42]
Answer:
 x = 4 
y =23 

work:
 plug in the value of Y to -2x-3y=-2. -2x - 3(<span>6x-1) = -2
 
multiply 3 and the numbers in parenthesis. -2x -18x - 3 =-2
combine like terms (-2x -18x). -20x - 3 = -2
subtract 3 from both sides to isolate the variable. -20x = -5 
divide to isolate the variable (-20/-5) x = 4
-
now that we know the value of x, it'll be easy to find Y.
Plug it in to the first equation.
</span><span>y=6(4)-1
</span>y = 24 - 1
y = 23

so x = 4 
and y = 23 

hope this helps! :D
7 0
3 years ago
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