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denpristay [2]
3 years ago
15

Which equation goes through the point (-7, 3) and is parallel to y = −8x + 1?

Mathematics
1 answer:
Ierofanga [76]3 years ago
4 0
I’m pretty sure it’s 3rd one
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you are renting a moving truck for a day. There is a dailyfee of $20 and a charge of $0.75 per mile. Your budget allows a maximu
11Alexandr11 [23.1K]

Answer:

its 6900000

Step-by-step explanation:

6hue and 388

8 0
3 years ago
Expand and simplify (y-3)³​
Tanya [424]

Answer:

Expanded: (y-3)(y-3)(y-3)

Simplified:  y^{3}-9y^{2}+27y-27

Step-by-step explanation:

Expanded: (y-3)(y-3)(y-3)

Simplified:

y^{2} -3y-3y+9(y-3)\\y^{2} -6y+9(y-3)

y^{3} -3y^{2}-6y^{2}  +18y+9y-27

y^{3}-9y^{2} +27y-27

5 0
3 years ago
A field researcher is gathering data on the trunk diameters of mature pine and spruce trees in a certain area. The following are
lidiya [134]

Answer:

As the pvalue of the test is 0.02097 < 0.1, using a .10 significance level, he can conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree.

Step-by-step explanation:

Using a .10 significance level, can he conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree

The null hypothesis is that they are equal(that is, subtraction between the means is 0), while the alternate hypothesis is that they are greater(that is, subtraction between the means is larger than 0). So

H_0: \mu_1 - \mu_2 = 0

H_a: \mu_1 - \mu_2 > 0

In which \mu_1 is the mean pine trees height while \mu_2 is the mean spruce trees height.

The test statistic is:

z = \frac{X - \mu}{s}

In which X is the sample mean, \mu is the value tested at the null hypothesis and s is the standard error.

0 is tested at the null hypothesis:

This means that \mu = 0

Mean trunk diameter (cm) 35 30:

Pine trees - 35

Spruce trees - 30

The sample mean is given by the subtraction of the means. So

X = 35 - 30 = 5

Sample Size 40 80

Population variance 160 160

This means that the standard error for each sample is given by:

s_1 = \frac{\sqrt{160}}{\sqrt{40}} = 2

s_1 = \frac{\sqrt{160}}{\sqrt{80}} = \sqrt{2}

The standard error of the difference is the square root of the sum squared of the standard error of each sample.

s = \sqrt{2^2 + (\sqrt{2})^2} = \sqrt{6} = 2.4495

Test statistic:

z = \frac{X - \mu}{s}

z = \frac{5 - 0}{2.4495}

z = 2.04

Pvalue of the test:

Probability of a sample mean larger than 5, which is 1 subtracted by the pvalue of Z when X = 5.

Looking at the z-table, z = 2.04 has a pvalue of 0.9793.

1 - 0.9793 = 0.0207

As the pvalue of the test is 0.02097 < 0.1, using a .10 significance level, he can conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree.

8 0
3 years ago
PLEASE HELP me
prohojiy [21]
To find the average number of customers for dinner, use the simple ratio of 5 lunch customers for every 8 dinner customers.

Because there are 40 lunch customers, this is eight groups of five lunch customers. This means you will need 8 groups of 8 dinner customers to make it equivalent.

8 x 8 = 64

There is an average of 64 customers for dinner.
4 0
3 years ago
What is factorisation ​
liubo4ka [24]

Factorization is a method of writing numbers as the product of their factors or divisors.

<em><u>Solution:</u></em>

<em><u>Factorisation:</u></em>

Factorization is a method of writing numbers as the product of their factors or divisors.

In other words we can say, Finding what to multiply together to get an expression.

It is like "splitting" an expression into a multiplication of simpler expressions.

<em><u>Methods of factorisation:</u></em>

  • Factoring out the GCF
  • The sum-product pattern
  • The grouping method
  • The perfect square trinomial pattern
  • The difference of squares pattern

<em><u>Factoring out the GCF:</u></em>

This methods means that factoring out common factors

For example:

12x^2 + 3x = 3x(4x + 1)

This can be used when each term in given expression shares a common factor

<em><u>The sum-product pattern</u></em>

A quadratic equation may be expressed as a product of two binomials

For example:

x^2 + 7x + 12 = (x + 3)(x + 4)

This method can be used for quadratic equations of form ax^2 + bx + c = 0

<em><u>The grouping method</u></em>

If the polynomial is of the form  ax^2 + bx + c and there are factors of ac that add up to b , we can use this method

For example:

2x^2 + 7x + 3\\\\2x^2 + 6x + 1x + 3\\\\2x(x + 3) + 1(x + 3)\\\\(x + 3)(2x + 1)

<em><u>The perfect square trinomial pattern</u></em>

If the first and last terms are perfect squares and the middle term is twice the product of their square roots , we can use this method

For example:

x^2 + 10x + 25\\\\(x + 5)^2

<em><u>The difference of squares pattern</u></em>

If the expression represents a difference of squares, we can use this method

Because a^2 - b^2 = (a + b)(a - b)

For example:

x^2 - 25\\\\x^2 - 5^2\\\\(x + 5)(x - 5)

6 0
3 years ago
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