Question

What is the permeter of square ABCD?

Answer 1

Answer:

24.3 units (3 s.f.)

Step-by-step explanation:

Since a square has 4 equal sides,

perimeter of ABCD= 4(length of AB)

Distance between 2 points

=$\sqrt{(y1 - y2)^{2} + (x1 - x2)^{2} }$

Length of AB

$= \sqrt{( { - 2 - 4)}^{2} + {(2 - 3)}^{2} } \\ = \sqrt{( - 6)^{2} + ( - 1)^{2} } \\ = \sqrt{37}$

perimeter of ABCD

$= 4 \sqrt{37} \\ = 24.3 \: units \: (3 \: s.f.)$