Oleg, Sasha, and Dima shared 600 toys. Sasha had twice as many toys as Oleg. Dima had 40 more toys than Oleg.
Let the number of toys Oleg has = x
Let the number of toys Sasha has = y
Let the number of toys Dima has = z
Sasha had twice as many toys as Oleg
So y = 2*x= 2x
Dima had 40 more toys than Oleg.
z = x + 40
Oleg, Sasha, and Dima shared 600 toys
x + y + z= 600
We know y=2x and z=x+40
Replace it for y and z
Subtract 40 on both sides
Divide by 4 on both sides
Oleg had 140 toys
= (4/9 .1/8 + 1/4): 5/16
= (4/72 + 1/4) : 5/16
= (1/18 + 1/4) : 5/16
= 11/36 : 5/16
= LCM of 16 and 36 is 144 so we have
44/144 : 45/144
= 44:45 Answer
Answer:
f(9/2) = 17/2
Step-by-step explanation:
f(x) = 3x-5
let x=9/2
f(9/2) = 3*9/2 -5
f(9/2) = 27/2 - 5
get a common denominator
f(9/2) = 27/2 - 10/2
f(9/2) = 17/2
Answer: At least 4/14 = 28.5%
Step-by-step explanation:
Select the location of a math book at the far end. The probability that the book next to it is a math book:
4 remaining math books, out of the 14 remaining books
In the middle, there are two potential spots adjacent to each book, so it could be higher - that’s why I say “at least” 4/14
Answer B would be correct because DE splits AC.
