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son4ous [18]
3 years ago
6

I may have alreadu asked this but...help !

Mathematics
1 answer:
Nataly_w [17]3 years ago
3 0
The first price is 18.934 and the second is 25.929 but I’m not sure about the third
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3t – 4(t – 5) + 5 for t=6. 2 ​
Trava [24]

Answer:

t = 18.8

Step-by-step explanation:

Hope this helped

please mar Brainliest

:)

5 0
3 years ago
Read 2 more answers
I WILL GIVE BRAILIEST PLEASE HELP
Mila [183]

Answer:

$3.49 for the muffin, and $2.96 for the coffee

Step-by-step explanation:

(3.25)(1.075) = 3.49

(2.75)(1.075) = 2.96

How to find the factor to multiply by

1.075 = 1+.075, 7.5% = 7.5/100 =  .075

3 0
3 years ago
Read 2 more answers
Please I need help and the calculation of which contract is better.
kramer

Answer:

You should go with the 1st, because it's cheaper.

Step-by-step explanation:

1st plan:

30$ which include 75 mins of free calls and 100 free text messages

25 more mins * 10¢ /min(0.1$/min) = 2.5$

You will pay 32.5$

2nd plan:

(calls)100*0.3$=30$

(text messages)100 * 0.1$=10$

30+10 = 40$

8 0
3 years ago
How many permutations can be formed from all the letters in the word engineering?
laila [671]

Answer:

277,200

Step-by-step explanation:

To find the number of permutation we can form from the letters of the word "engineering", we first need to find the frequencies of the different letters present.

E = 3

G = 2

N= 3

I = 2

R = 1

Now that we have the frequencies, we count the number of letters in the word "engineering".

E N G I N E E R I N G

11 letters

Now we take the factorial of total number of letters and divide it by the number of repeats and their factorial

So we get:

\dfrac{11!}{3!2!3!2!1!}

We remove the 1! because it will just yield 1.

\dfrac{11!}{3!2!3!2!}

So the total number of permutations from the letters of the word "engineering" will be:

Total number of permutations = \dfrac{39,916,800}{144}

Total number of permutations = 277,200

3 0
3 years ago
PLEASE HELP!!! <br> BRAINLYEST!!!
11Alexandr11 [23.1K]

Answer:

C

Step-by-step explanation:

Using the rule of exponents

\frac{a^{m} }{a^{n} } = a^{(m-n)}

Note that 8 = 2³, thus

\frac{2^{5} }{8}

= \frac{2^{5} }{2^{3} }

= 2^{(5-3)}

= 2²

7 0
3 years ago
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