Answer:
public ArrayList onlyBlue(String[] clothes){
ArrayList<String> blueCloths = new ArrayList<>();
for(int i =0; i<clothes.length; i++){
if(clothes[i].equalsIgnoreCase("blue")){
blueCloths.add(clothes[i]);
}
}
return blueCloths;
}
Explanation:
- Create the method to accept an Array object of type String representing colors with a return type of an ArrayList
- Within the method body, create and initialize an Arraylist
- Use a for loop to iterate the Array of cloths.
- Use an if statement within the for loop to check if item equals blue and add to the Arraylist.
- Finally return the arrayList to the caller
I have been running into the same problem, they haven't said anything but that might be the case.
Yes, click CTRL + F at the same time and a small search bar will pop up on the top right of your screen
Answer / Explanation:
#include <iostream>
using namespace std;
int main()
{
int userNum = 0;
userNum = 20;
cout << userNum << " ";
while (userNum > 1)
{
userNum = userNum/2;
cout << userNum << " ";
}
cout << endl;
return 0;
}
However, we should note that the above codes divides properly but when it gets to 0, it will always give output as 0 instead of terminating the program.
Hence to make it terminate, we include:
while (userNum > 1)
{
cout << userNum << " ";
userNum = userNum/2;
}
The above code alternatively should be replaced with int userNum = 0; .
Also, for the sake of industry best standard and the general principle, we can say:
The general principle is:
while ( <conditional> )
{
// Use the data
// Change the data as the last operation in the loop.
}
A for loop provides natural placeholders for these.
for ( <initialize data>; <conditional>; <update data for next iteration> )
{
// Use the data
}
If you were to switch to using a for loop, which I recommend, your code would be:
for ( userNum = 20; userNum > 0; userNum /= 2 )
{
cout << userNum << " ";
