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Aleksandr-060686 [28]
3 years ago
14

What is the magnitude of the force exerted by the biceps fbiceps? What is the magnitude of the force exerted by the elbow felbow

?
Biology
1 answer:
Slav-nsk [51]3 years ago
8 0

Answer:

<u> </u><u>The magnitude of the force exerted by the biceps </u>f_b_i_c_e_p_s<u> is 218.38N</u>

<u>The magnitude of the force exerted by the elbow </u>f_e_l_b_o_w<u> is 194.37N</u>

Explanation:

Firstly , lets calculate the magnitude of force exerted by biceps f_b_i_c_e_p_s -

Mass of the forearm=

m_f=1.50kg

Mass of the ball =

m_b_a_l_l=950g

   = 0.950kg

so, weight of the forearm=

w_f=m_f g

weight of the ball=

w_b_a_l_l=m_b_a_l_l g

Now , balancing torque about the elbow , we have-

F_b_i_c_e_p_s\times d_b_i_c_e_p_s= w_f\times\frac{d_b_a_l_l}{2} + w_b_a_l_l\times d_b_a_l_l

(here , distance of the bicep is 2.50cm = 0.025m and distance of the ball is 36cm= 0.36m)

Now putting the given values in the formula -

F_b_i_c_e_p_s\times 0.025= 0.95\times9.8\times\frac{0.36}{2} +1.50\times 0.36

F_b_i_c_e_p_s=218.38N

Now, lets calculate the force exerted by elbow F_e_l_b_o_w -

Balancing the vertical forces

F_b_i_c_e_p_s=F_e_l_b_o_w+w_f+w_b_a_l_l

F_e_l_b_o_w = 218.38-(1.00\times9.8)-(0.95\times9.8)

F_e_l_b_o_w=194.37N

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