Answer:
8h + 15 = 39
Step-by-step explanation:
The base fee is 15 so you shouldn't multiply the hours by it.
The question states 8 per hour which means that you should multiply the 8 by hours and add on the base fee which is 15.
Answer:
Ok, first in our series we can see two numbers in the Sigma, one bellow 0, and other above, 4.
This means that the value of k will go from 0 to 4, then all the numbers in the sum are:
(-1/2)^0 + (-1/2)^1 + (-1/2)^2 + (-1/2)^3 + (-1/2)^4
So we have 5 terms in our series.
b) to see the sign in each term, we must solve the powers, remember that:
(-1)^n is -1 if n is odd, and is equal to 1 if n is even, so we have:
(-1/2)^0 + (-1/2)^1 + (-1/2)^2 + (-1/2)^3 + (-1/2)^4
= 1 -1/2 + 1/4 - 1/8 + 1/16.
So the sign in each term of the series alternates.
Answer:
$637.50
Step-by-step explanation:
According to the Question,
- Given That, A seller of the property listed at $200,000 excepted a 90% offer the home appraised at $185,000 and the buyers obtained a loan for 85% for 30 years at 5% interest
Thus, the first months interest is
$200,000 list price x 0.90 = $180,000 contract sales price.
Since lender always uses the less of the appraised value or the contract sales price, use $180,00 for the remainder of the calculations.
- $180,000 contract sales price x 0.85 LTV = $153,000 loan.
- $153,000 loan x 0.05 interest rate = $7,650 annual interest.
- $7,650 ÷ 12 = $637.50 monthly interest payment for the first month.
Given :
A function , x = 2cos t -3sin t .....equation 1.
A differential equation , x'' + x = 0 .....equation 2.
To Find :
Whether the given function is a solution to the given differential equation.
Solution :
First derivative of x :

Now , second derivative :

( Note : derivative of sin t is cos t and cos t is -sin t )
Putting value of x'' and x in equation 2 , we get :
=(-2cos t + 3sin t ) + ( 2cos t -3sin t )
= 0
So , x'' and x satisfy equation 2.
Therefore , x function is a solution of given differential equation .
Hence , this is the required solution .