Answer:
A
Step-by-step explanation:
first lets find the area of the square
A=l*w
12*12=144 m^2
then lets find the are of the circle
A=pi*r^2
A=3.14*(d/2)^2
the diameter of the circle is 12m
A=3.14*(12/2)^2
A=3.14*(6)^2
A=3.14*36
A=113.04 m^2
Now, lets subtract the area of the circle form the area of the square
144-113.04= 30.96 m^2
So, the answer is A
if a b 9 are in GP
b÷a = 9 ÷ b
b^2 = 9a
if a - 1 b 9 are in AP
2b = a+8
b = a+8÷2
substitute
b is equal to a + 8 by 2 in b square equal to 9 a
(a+8÷2)^2 = 9a
a^2+16a+64 = 36a
a^2 -20a +64 =0
(a-16) (a-4) =0
a= 16 or a=4
when a=16 b= 12
when a=4 b= 6
Value of a and b are given above
150, 155, 163, 168, 172, 177, 186, 190, 205
Hhjhhhu did I need ooo 40
3+5+2+6=16 in each bag multiply or divide sorry not that much of an answer
