Answer:
1) 2-bromobutane
2) 1-bromobutane
Explanation:
In the HBr reaction, we will have a <u>markovniknov reaction</u> due to the <u>carbocation formation</u>. The Br- then would be added in the <u>most substituted</u> carbon of the double bond.
In the HBr/peroxide reaction we have the opposite case: an <u>anti-markovnikov reaction</u>. Therefore the Br- would be added in the <u>least substitued</u> carbon of the double bond.
Hey there!:
Concentration of NaOH = 0.200 M
Concentration of HNO₃= 0.200 M
Total volume = 50.0 mL + 60.0 mL = 110 mL=> 0.11 L
The neutralization reaction between NaOH and HNO3 :
OH⁻ + H⁺ ----------> H₂O
So :
n ( H⁺ ) = 60 mL * 0.200 M / 1000 mL => 0.012 moles of H⁺
n ( OH⁻ ) = 50 mL 0.200 M / 1000 mL => 0.01 moles of OH⁻
Hence OH⁻ is limiting reagent .
Remaining moles of H⁺ = 0.012 - 0.01 => 0.002 moles
Concentration of H⁺ = 0.002 M / 0.11 L
Concentration of H⁺ = 0.01818 moles/L
Therefore:
pH = - log [ H⁺ ]
pH = - log [ 0.01818 ]
pH = 1.74
Hope that helps!
Answer:
elbow
Explanation:
These terms are replaced by: Proximal: Closer to the point of attachment with the torso. In other words, closer to the shoulder or the hip. The elbow is proximal to the wrist.
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Answer:
Here you can use the Clausis Clayperon equation: ln P1/P2=-Ea/R-(1/T1 - 1/T2)
where P1 is the pressure at standard condition: 760 mm Hg
P2 is the variable we need to solve
Ea is the activation energy, which in this case is delta H vaporisation: 56.9 kJ/mol
R is the gas constant 8.314 J/mol or 8.314 J/mol /1000 to convert to kJ
T1 is the normal boiling point 356.7 C, but converted to Kelvin: 629.85K
T2 is room temperature 25 C, but converted to Kelvin: 298.15 K
Once you plug everything in, you should get 4.29*10^-3 mmHg
Explanation:
