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DIA [1.3K]
3 years ago
10

The normal boiling point of mercury (Hg) is 356.7 °C. What is the vapor pressure of mercury at 333 °C in atm? (∆Hvap = 58.51 kJ/

mol
Chemistry
1 answer:
grigory [225]3 years ago
8 0

Answer:

Here you can use the Clausis Clayperon equation: ln P1/P2=-Ea/R-(1/T1 - 1/T2)

where P1 is the pressure at standard condition: 760 mm Hg

P2 is the variable we need to solve

Ea is the activation energy, which in this case is delta H vaporisation: 56.9 kJ/mol

R is the gas constant 8.314 J/mol or 8.314 J/mol /1000 to convert to kJ

T1 is the normal boiling point 356.7 C, but converted to Kelvin: 629.85K

T2 is room temperature 25 C, but converted to Kelvin: 298.15 K

Once you plug everything in, you should get 4.29*10^-3 mmHg

Explanation:

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Consider the following data for five hypothetical elements: Q, W, X, Y, and Z. Rank the elements from most reactive to least rea
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Answer:

Y, Q, W, Z and X

Y > Q > W > Z > X

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To know the most reactive element, the element will be able to displace other metal in it compound. We also have to observe if the reaction occur. If the reaction didn't occur, that means the element is not reactive than the metal found in the other reactant. Invariably their will be no displacement.

Q + w+ Reaction occurs

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x +z+ No reaction

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