The sampling distribution of x has a mean μₓ = <u> μ </u> and standard deviation σₓ = <u> σ/√n </u>.
In the question, we are given that a random sample of size n is drawn from a large population with mean μ and standard deviation σ.
We are asked to find the mean and the standard deviation for the sampling distribution of the variable x for this sample.
The sample mean is regularly distributed, with a mean μₓ = μ and standard deviation σₓ = σ/√n, where n is the sample size, for samples of any size taken from populations that have a normal distribution.
Thus, the sampling distribution of x has a mean μₓ= <u> μ </u> and standard deviation σₓ= <u> σ/√n </u>.
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The provided question is incomplete. The complete question is:
"Fill in the blanks to correctly complete the sentence below.
Suppose a simple random sample of size n is drawn from a large population with mean μ and standard deviation σ.
The sampling distribution of x has mean μₓ =______ and standard deviation σₓ =______."
The answer to this question is x=8; y= -7
The independent quantity is 20-25 hours per week because time will go on no matter what. The dependent quantity is the amount of money Windiest is paid per hour.
You will have to type it into Microsoft word first, type a number or algebraic expression into a Word document. Press the "Ctrl," "Shift" and "=" keys on your keyboard to turn on the Superscript mode. Enter another number or expression signifying the exponent.
Hope this helps! :)
As shown... where? I have no idea what you are talking about or referencing to.
