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Ugo [173]
3 years ago
6

Which combination of variables will make an experiment the most reliable? A. Once controlled variable and many experimental vari

ables. B. Two controlled variables C. Two experimental Variables D. One dependent variable and one experimental variable
Chemistry
1 answer:
pav-90 [236]3 years ago
6 0

Answer:

D. One dependent variable and one experimental variable

Explanation:

The experimental variable is defined as an independent variable which can be manipulated during an experiment in order to find out its impact or influence on the dependent variable.

The dependent variable refers to a variable that changes when an experimental or  independent variable is manipulated.

Every experiment must have at least one experimental variable and one dependent variable in order to yield any meaningful result.

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Hydrogen is 99% H-1, 0.8% H-2 , and 0.2 H-3. calculate its average atomic mass
AlekseyPX
A= (99x1+0,8x2+0,2x3)÷100%=1,012
1,012≈1

5 0
4 years ago
Balance equation for. _Mg + _H3(PO4) --_Mg3(PO4)2+ _H2
Katena32 [7]
3Mg + 2H3(PO4) —> Mg3(PO4)2 + 3H2

I think
3 0
3 years ago
What is a real-life example of equilibrium and what would happen if there was a shift in the system of that example?
BabaBlast [244]

Answer:

Refrigerator

Explanation:

Think about it. Equilibrium is between 2 "places", and if you didn't open the fridge, there would be a buildup of cold air.

Because of that buildup, it would keep getting colder until it isn't possible to get cold anymore. That is equilibrium.

However, if you were to open the door for a very, very long time, you would lower the temp. inside the fridge, therefore causing for the room you are in to be slightly colder, and the fridge to decrease in cold. The fridge will still be slightly cold, but it won't be lukewarm if you leave it for 2 hours. (Unless it's broken)

That is equilibrium :)

3 0
2 years ago
What type of wave makes up sound
Zielflug [23.3K]
Sound waves, I'm pretty sure.
5 0
3 years ago
A chemist wishing to do an experiment requiring 47Ca2+(half-life = 4.536 days) needs 5.00 g of the nuclide. What mass of 47CaCO
Artyom0805 [142]

Answer: The answer is 6.78 grams.

Explanation: The equation used for solving this type of problems  is:

\frac{N}{N_0}=(\frac{1}{2})^n

where, N_0 is the initial amount of radioactive substance, N is the remaining amount and n is the number of half lives.

Number of half lives is calculated on dividing the given time by the half life.

n = time/half life

Time is given as 48.0 hours and the half life is given as 4.536 days. let's make the units same and for this let's convert the half life from days to hours.

4.536days(\frac{24hours}{1day})

= 108.864 hours

So, n=\frac{48.0}{108.864}  = 0.441

Since 5.00 g is the required amount when the radioactive substance is delivered to the scientist, it would be the final amount that is N. We need to calculate the initial amount. Let's plug in the values in the equation:

\frac{5.00}{N_0}=(\frac{1}{2})^0^.^4^4^1

\frac{5.00g}{N_0}=0.737

N_0=\frac{5.00g}{0.737}

N_0 = 6.78 g

So, 6.78 g of the radioactive substance needs to be ordered.

4 0
4 years ago
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