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4 years ago

The what and what properties of a substance affect how substances in a mixture seperate

Chemistry

1 answer:

kompoz [17]4 years ago

7 0

Psychical(you see the changes visible) and Chemical properties(they react and combine, you may see fizzing or bubbles).

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Complete and balance the molecular equation for the reaction of aqueous sodium carbonate, Na 2 CO 3 Na2CO3 , and aqueous nickel(

antoniya [11.8K]

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of sodium carbonate and nickel (II) chloride is given as:

$Na_2CO_3(aq.)+NiCl_2(aq.)\rightarrow 2NaCl(aq.)+NiCO_3(s)$

Ionic form of the above equation follows:

$2Na^{+}(aq.)+CO_3^{2-}(aq.)+Ni^{2+}(aq.)+2Cl^{-}(aq.)\rightarrow NiCO_3(s)+2Na^+(aq.)+2Cl^-(aq.)$

As, sodium and chloride ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$Ni^{2+}(aq.)+CO_3^{2-}(aq.)\rightarrow NiCO_3(s)$

Hence, the net ionic equation is written above.

3 0

4 years ago

JWhat type of evidence is gathering information through your senses or using scientific tools?

Ad libitum [116K]

Observations etc etc

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3 years ago

What is the specific heat of a substance that absorbs 2500 joules of heat when a sample of 100g of the substance increases in te

Ierofanga [76]

Answer:

0.417 J/gºC

Explanation:

From the question given above, the following data were obtained:

Heat (Q) absorbed = 2500 J

Mass (M) of substance = 100 g

Initial temperature (T1) = 10 °C

Final temperature (T2) = 70 °C

Specific heat capacity (C) =?

Next, we shall determine the change in temperature (ΔT). This can be obtained as follow:

Initial temperature (T1) = 10 °C

Final temperature (T2) = 70 °C

Change in temperature (ΔT) =?

Change in temperature (ΔT) = T2 – T1

Change in temperature (ΔT) = 70 – 10

Change in temperature (ΔT) = 60 °C

Finally, we shall determine the specific heat capacity of the substance as follow:

Heat (Q) absorbed = 2500 J

Mass (M) of substance = 100 g

Change in temperature (ΔT) = 60 °C

Specific heat capacity (C) =?

Q = MCΔT

2500 = 100 × C × 60

2500 = 6000 × C

Divide both side by 6000

C = 2500 / 6000

C = 0.417 J/gºC

Therefore, the specific heat capacity of substance is 0.417 J/gºC

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3 years ago

What fruit does orange fanta taste like??

miv72 [106K]

Answer:

royal

Explanation:

royal is made of orange also

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3 years ago

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Please. If you’re good at this stuff shouldn’t be too bad.

Grace [21]

Answer:

im sorry im not sure

Explanation:

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3 years ago