Answer:
26.8g
Explanation:
The formula of the compound given is:
Cu₂CrO₄
Given:
Number of moles = 0.11
To find the mass, we use the expression below:
Mass = number of moles x molar mass
Molar mass of Cu₂CrO₄ = 2(63.6) + 52 + 4(16) = 243.2g/mol
Now insert the parameters and solve;
Mass = 0.11 x 243.2 = 26.8g
The mass of carbon dioxide that would be produced will be 22 kg
<h3>Combustion of carbon</h3>
The combustion of carbon in air can be represented by the equation:
C + O2 ---> CO2
The mole ratio of C to O2 to CO2 is 1:1:1.
Mole of 6kg of carbon = mass/molar mass
= 6000/12
= 500 moles
Equivalent mole of CO2 produced = 500 moles
Mass of 500 moles CO2 = mole x molar mass
= 500 x 44.01
= 22,005 g or 22 kg approximately
More on combustion reactions can be found here: brainly.com/question/13649083
For Ar :
1 mol ------------ 22.4 L ( at STP )
7.6 mol ---------- x L
x = 7.6 * 22.4
x = 170.24 L
-----------------------------------------------------------------
For C2H3:
1 mol ------------ 22.4 ( at STP)
0.44 mol --------- y L
y = 0.44 * 22.4
y = 9.856 L
hope this helps !.
Hydrogen bonding occurs when hydrogen is bonded to an oxygen or nitrogen or fluorine atom. In this case, the hydrogen atom in a hydrogen fluoride molecule will be able to bond to the fluoride atom of another hydrogen fluoride molecule, forming a hydrogen bond.
Answer:
See explanation
Explanation:
From left to right, the oxides across period 3;
i) Period 3 oxides all appear white in colour. They are all crystalline solids and their melting points decrease from left to right.
ii) The volatility of period 3 oxides increases from left to right across the periodic table
iii) The metallic oxides on the right hand side adopt giant ionic structures. Silicon oxide which is in the middle of the period forms a giant covalent structure. Oxides of other elements towards the right hand side form molecular oxide structures.
iv) The acidity of oxides of period 3 increases from left to right. Metals on the left hand side form basic oxides while non-metals on the right hand side form acidic oxides. The oxide of aluminium in the middle is amphoteric.
v) The oxides of period 3 elements do not conduct electricity. However, the metallic oxides on the lefthand side conduct electricity in molten state. The non-metallic oxides on the right hand side are molecular hence they do not conduct electricity under any circumstance.
