All categories

4 years ago

Explain why neptune cannot be seen without a telescope

Chemistry

1 answer:

Law Incorporation [45]4 years ago

8 0

Because it's to little

You might be interested in

Which property of a body cannot be changed if a force is applied to it?

prohojiy [21]

The answer is it’s mass

8 0

4 years ago

Read 2 more answers

At a certain temperature, the solubility of n2 gas in water at 3.08 atm is 72.5 mg of n2 gas/100 g water . calculate the solubil

8090 [49]

According to Henry's law, solubility of solution is directly proportional to partial pressure thus,

$\frac{S_{1}}{P_{1}}=\frac{S_{2}}{P_{2}}$

Solubility at pressure 3.08 atm is 72.5/100, solubility at pressure 8 atm should be calculated.

Putting the values in equation:

$\frac{0.725}{3.08}=\frac{S_{2}}{8}$

On rearranging,

$S_{2}=\frac{0.725\times 8}{3.08}=1.88$

Therefore, solubility will be 1.88 mg of $N_{2}$ gas in 1 g of water or, 188 mg of tex]N_{2}[/tex] gas in 100 g of water.

3 0

3 years ago

___________ is a chemical process that lyses, or splits, molecules by the addition of water functioning in disassembly of polyme

inysia [295]

Answer:

The answer is: Hydrolysis

Explanation:

Hydrolysis is the chemical method in which water molecule is added to a molecule, which leads to the cleavage of one or more chemical bonds in the molecule. In this reaction, the water molecule acts as a nucleophile and breaks down the large molecules like polymers into smaller molecules such as monomers. Hydrolysis reaction includes fragmentation, elimination substitution reactions.

5 0

3 years ago

Effect of fossil fuel emission on oceans?

BlackZzzverrR [31]

Fossil fuel emissions can create acid rain, which in turn increases the pH of ocean water, harming the organisms in the ocean.<span />

7 0

4 years ago

The heat of reaction for the combustion of propane is –2,045 kJ. This reaction is: C3H8(g) +502 (g) 3CO2 (g) + 4H2O (g). Determi

Ede4ka [16]

Answer:

$\Delta _fH_{C_3H_8}=-102.7kJ/mol$

Explanation:

Hello,

In this case, we can consider that the given heat of combustion is indeed the heat of reaction since it corresponds to the combustion of propane, which is computed by using the heat formation of all the involved species as shown below:

$\Delta _cH=3*\Delta _fH_{CO_2}+4*\Delta _fH_{H_2O}-\Delta _fH_{C_3H_8}-5*\Delta _fH_{O_2}$

Thus, since the heat of formation of gaseous carbon dioxide is -393.5 kJ/mol, water -241.8 kJ/mol and oxygen 0 kJ/mol, the heat of formation of propane is:

$\Delta _fH_{C_3H_8}=3*\Delta _fH_{CO_2}+4*\Delta _fH_{H_2O}-5*\Delta _fH_{O_2}-\Delta _cH\\\\\Delta _fH_{C_3H_8}=3*(-393.5)+4*(-241.8)-5*0-(-2045)\\\\\Delta _fH_{C_3H_8}=-102.7kJ/mol$

Best regards.

8 0

3 years ago