Answer: if Gregory draws the segment with endpoints A and A’, then the midpoint will lie on the line of reflection.
Explanation:
Given that a triangle ABC is reflected in triangle A'B'C'
Here reflection is done on a line
If you imagine the line as a mirror then ABC will have image on the mirror line as A'B'C'
Recall that in a mirror the object and image would be equidistant from the mirror and also the line joining the image and object would be perpendicular to the mirror
But note that corresponding images will only be perpendicular bisector to the line
So A and A' only will be corresponding so AA' will have mid point on line
Option 1 is right
Answer:
c:(0;+∞)
Step-by-step explanation:
Given the situation, that the square root function only allows you values above than "0" (not equal neither), then you must consider that every value above 0 belongs to it's domain.
Then, to express the domain, going from your most negative number, to your most possitive number (in this case all positive number, thats why we use infinite) you must use the parenthesis wich means, you are not considering the value (in this case 0), but the value right after it, to the next value that as we said before, is inifinite. Also remember, that when you express a domain, and use infinite (despite it's going to negative way, or possitive way, it also goes with parenthesis).
Answer:
<h2>hope it helps you see the attachment for further information </h2>
Answer:
Tan x= 3/4 Cos x= 4/5 Sin x=3/5
Step-by-step explanation:
"soh-cah-toa"
Just an easy way to remember how Sine, Cosine and Tangent work:
Soh...
Sine = Opposite / Hypotenuse
...cah...
Cosine = Adjacent / Hypotenuse
...toa
Tangent = Opposite / Adjacent
Answer:
i think 42
Step-by-step explanation:
