Question

A company produces fruity drinks that contain a percentage of real fruit juice. Drink A contains 20% real fruit juice and Drink B contains 15% real fruit juice. The company used 100.5 liters of real fruit juice to make 30 more liters of Drink A than liters of Drink B. Write a system of equations that could be used to determine the number of liters of Drink A made and the number of liters of Drink B made. Define the variables that you use to write the system.

Answer 1

Answer:

There needs to be 300 liters of Drink A and 270 liters of Drink B

Step-by-step explanation:

Let a = the amount of Drink A and b = the amount of Drink B

Multiplying a number by 0.2 is the same as calculating 20% of it and same goes with 15% and 0.15. This makes our equation for the amount of fruit juice:

0.2a + 0.15b = 100.5

We know what the difference between a and b will be 30 liters so:

a - b = 30

Now we have our system of equations

To cancel out a, we can multiply the first equation by -5 so we will now have:

-a - 0.75b = -502.5

a - b = 30

Adding these two equations together, we get:

-1.75b = -472.5

Both sides are negative, so we can take the negative signs away.

1.75b = 472.5

Now divide both sides by 1.75

b = 270

Plugging 270 into b, we have:

a - b = 30

a - 270 = 30

Add 270 to both sides

a = 300

There needs to be 300 liters of Drink A and 270 liters of Drink B

Answer 2

Answer:

70L of Drink B and 100L of Drink A