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oksian1 [2.3K]
3 years ago
15

Y is directly proportional to the square of x.

Mathematics
1 answer:
RUDIKE [14]3 years ago
5 0

Answer:

The value of y is 847 for x=11

Step-by-step explanation:

It is given that y is directly proportional to the square of x

This can be written mathematically as:

y \propto  x^2

Removing the proportionality symbol introduces a proportionality constant in the equation which is denoted by k

y = kx^2

Given that "When x is 5, y is 175"

175 = k (5)^2\\175 = k*25\\k = \frac{175}{25}\\k = 7

Putting the value of k

y = 7x^2

Now putting x = 11

y = 7(11)^2\\y = 7 * 121\\y = 847

Hence,

The value of y is 847 for x=11

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What 2 numbers multiply to get 10 and add to get 7?
Xelga [282]
5x2=10
5+2= 7

Answer: 5 and 2
5 0
2 years ago
Evaluate the function below for x=2. F(x)=x^4+6x^3+3
Nitella [24]
Answer:
f(2)=67
Step-by-step explanation:
In order to evaluate the function f(x)=x^4+6x^3+3 for x=2, you must replace all of the x's with the number two and then simplify:
f(2)=2^4+6(2)^3+3
f(2)=16+6(8)+3
f(2)=16+48+3
f(2)=16+51
f(2)=67
7 0
3 years ago
What is the best approximation for the circumference of a circle with a diameter of 400 inches? Use 3.14 to approximate pi.
vesna_86 [32]

Answer:

C≈1256.64in

Step-by-step explanation:

C=πd=π·400≈1256.63706in

Hope this helps!

3 0
3 years ago
PLEASE HELP!!!!
iris [78.8K]
I hope this helps you

7 0
3 years ago
a particular city had a population of 24,000 in 1900 and a population of 29,000 in 1920. Assuming that its population continues
DerKrebs [107]

Answer:

It will have a population of 61,779 in 2000.

Step-by-step explanation:

The population for the city, in t years after 1900, can be modeled by a exponential function with constant growth rate in the following format:

P(t) = P(0)(1+r)^{t}

In which P(0) is the population in 1900 and r is the growth rate.

Population of 24,000 in 1900

This means that P(0) = 24000

Population of 29,000 in 1920.

1920 is 1920 - 1900 = 20 years after 1900.

This means that P(20) = 29000. So

P(t) = P(0)(1+r)^{t}

29000 = 24000(1+r)^{20}

(1+r)^{20} = \frac{29000}{24000}

\sqrt[20]{(1+r)^{20}} = \sqrt[20]{\frac{29000}{24000}}

1 + r = 1.0095

So

P(t) = P(0)(1+r)^{t}

P(t) = 24000(1.0095)^{t}

What population will it have in 2000

2000 is 2000 - 1900 = 100 years after 1900. So this is P(100).

P(t) = 24000(1.0095)^{t}

P(100) = 24000(1.0095)^{100} = 61779

It will have a population of 61,779 in 2000.

4 0
3 years ago
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