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sukhopar [10]
3 years ago
13

What is the equation to the line that goes through the point

Mathematics
1 answer:
DochEvi [55]3 years ago
5 0

Step-by-step explanation:

perpendicular slope is negative reciprocal. -1/-1 = 1

y - 4 = x +3

y = x + 7

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A population of 55 foxes in a wildlife preserve doubles in size every 14 years. The function y equals 55 times 2 Superscript x ​
Pavlova-9 [17]
Since <em>x</em> is the number of 14-year periods, the first thing we do is divide 28 years by 14. 28/14=2.  Now we use that in our function, y=55*2^x.

y=55*2^2=55*4=220
There will be 220 foxes after 28 years.
6 0
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Triangle ABC is translated to triangle A'B'C' by the following motion rule.<br><br> (x,y)→(x+2,y−5)
Nata [24]

Answer:

The answer for this question is A. (4,-4)

5 0
3 years ago
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The cost per mile driven represents the slope of the function. So b. 15 cents per mile driven is the slope-the price increases as the number of miles increase.
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Which graph represents the solution to the system of equations y=3x+2 10x+2y=20
Step2247 [10]

Answer:

The graph in the attached figure

Step-by-step explanation:

we have

y=3x+2 ----> equation A

10x+2y=20 ----> equation B

Solve the system by graphing

Remember that the solution of the system is the intersection point both graphs

Using a graphing tool

The intersection point is (1,5)

see the attached figure

therefore

The solution of the system is the point (1,5)

7 0
3 years ago
Help based offf order of operations please help
JulijaS [17]

Answer:

The answer for :

h. \:  \:   \: \frac{5}{6}

i. \:  \:  \:  \frac{35}{32}

k. \:  \:  \:  \frac{-29}{20}

l. \:  \:  \:  \frac{13}{15}

Step-by-step explanation:

Question h:

\frac{2}{3}  + ( \frac{1}{3}  \times  \frac{1}{2} )

=  \frac{2}{3}  +  \frac{1}{6}

=  \frac{2 \times 2}{3 \times 2}  +  \frac{1}{6}

=  \frac{4}{6}  +  \frac{1}{6}

=  \frac{5}{6}

Question i:

\frac{7}{8}  +  \frac{1}{4}  \times ( \frac{3}{2}  -  \frac{5}{8} )

=  \frac{7}{8}  +  \frac{1}{4}  \times ( \frac{3 \times 4}{2 \times 4}  -  \frac{5}{8} )

= \frac{7}{8}  +  \frac{1}{4}  \times ( \frac{12}{8}  -  \frac{5}{8} )

=  \frac{7}{8}  +  (\frac{1}{4}  \times  \frac{7}{8} )

=  \frac{7}{8}  +  \frac{7}{32}

=  \frac{7  \times 4}{8 \times 4}  +  \frac{7}{32}

=  \frac{28}{32}  +  \frac{7}{32}

=  \frac{35}{32}

Question k:

\frac{3}{4}  - ( \frac{12}{7}  \div  \frac{12}{21} ) +  \frac{4}{5}

=  \frac{3}{4}  - ( \frac{12}{7}  \times  \frac{21}{12} ) +  \frac{4}{5}

=  \frac{3}{4}  -  \frac{3}{1}  +  \frac{4}{5}

= \frac{3 \times 5}{4 \times 5}  -  \frac{3 \times 20}{1 \times 20} +  \frac{4 \times 4}{5 \times 4}

=  \frac{15}{20}   -   \frac{60}{20} +  \frac{16}{20}

=  -  \frac{29}{20}

Question l:

\frac{5}{2}  \times ( \frac{2}{3}  -  \frac{1}{5} ) - ( \frac{2}{5}  \div  \frac{4}{3} )

=  \frac{5}{2}  \times ( \frac{2 \times 5}{3 \times 5}  -  \frac{1 \times 3}{5 \times 3} ) - ( \frac{2}{5}  \times  \frac{3}{4} )

=  \frac{5}{2}  \times ( \frac{10}{15}  -  \frac{3}{15} ) -  \frac{3}{10}

=  (\frac{5}{2} \times   \frac{7}{15}) -  \frac{3}{10}

=  \frac{7}{6}  -  \frac{3}{10}

=  \frac{7 \times 5}{6 \times 5}  -  \frac{3 \times 3}{10 \times 3}

=  \frac{35}{30}  -  \frac{9}{30}

=  \frac{26}{30}

=  \frac{13}{15}

8 0
3 years ago
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