Answer:
Center at (4, 7) and radius is √49, or 7
Step-by-step explanation:
Didn't you mean (x-4)² + (y-7) ² = 49?
Comparing (x-4)² + (y-7) ² = 49
to (x - h)^2 + (y - k)^2 = r^2, we see that the center is at (h, k) => (4, 7) and that the radius is √49, or 7.
Answer:
The answer is B. 
Step-by-step explanation:
...
bearing in mind that standard form for a linear equation means
• all coefficients must be integers, no fractions
• only the constant on the right-hand-side
• all variables on the left-hand-side, sorted
• "x" must not have a negative coefficient

![\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-7=1[x-(-1)]\implies y-7=x+1 \\\\\\ y=x+8\implies \boxed{-x+y=8}\implies \stackrel{\textit{standard form}}{x-y=-8}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y-y_1%3Dm%28x-x_1%29%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%5Cimplies%20y-7%3D1%5Bx-%28-1%29%5D%5Cimplies%20y-7%3Dx%2B1%20%5C%5C%5C%5C%5C%5C%20y%3Dx%2B8%5Cimplies%20%5Cboxed%7B-x%2By%3D8%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bstandard%20form%7D%7D%7Bx-y%3D-8%7D)
just to point something out, is none of the options, however -x + y = 8, is one, though improper.
Answer:
312
Step-by-step explanation:
T.S.A : ( 2 × L × w ) + ( 2 × h × w ) + ( 2 × L × h ) = Area
9 - 3 = 6 - 3 = 3
( 2 × 12 × 3 ) + ( 2 × 8 × 3 ) + ( 2 × 12 × 8 ) = Area
72 + 48 + 192 = 312
4(2k - 3) + 1 = 8k - 11
8k - 12 + 1 = 8k - 11
8k - 11 = 8k - 11
So, these two equations equal to the same thing.
Glad I could help and gave a fantastic day!